The area of a rectangle is 507 centimeters squared. The length is 3 times the width. What is the length of the rectangle? 1) 3 cm 2) 13 cm 3) 26 cm 4) 39 cm

Answers

Answer 1
Answer:

Answer:

option 4

Step-by-step explanation:

the area (A) of a rectangle is calculated as

A = length × width

let width be w then length = 3w ( 3 times the width )

given A = 507

substitute these values into the formula for A

507 = 3w × w , that is

507 = 3w² ( divide both sides by 3 )

169 = w² ( take square root of both sides )

√(169) = √(w^2) , that is

13 = w

Then

length = 3w = 3 × 13 = 39 cm


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Is this correct? The answer I picked was the only one that had no limit. If I did it correctly the other choices limit was zero.

Answers

Step-by-step explanation:

These are all examples of p-series:

∑(1 / nᵖ), where p>0.

If p > 1, the series converges.  If 0 < p ≤ 1, the series diverges.

First option:

∑(1/n⁵)

Here, p = 5.  Since 5 > 1, the series converges.

Second option:

∑((√n+3)/n³)

∑((√n)/n³) + ∑(3/n³)

∑(1/n^2.5) + 3 ∑(1/n³)

In the first sum, p = 2.5.  In the second sum, p = 3.  Both are greater than 1, so the series converges.

Third option:

∑((n−4)/(n⁴√n))

∑(1/(n³√n)) − ∑(4/(n⁴√n))

∑(1/n^3.5) − 4 ∑(1/n^4.5)

In the first sum, p = 3.5.  In the second sum, p = 4.5.  Both are greater than 1, so the series converges.

Fourth option:

∑(1/∛n)

∑(1/n^⅓)

Here, p = ⅓.  This is less than 1, so the series diverges.

Note: if a series is converging, then the limit is 0.

However, if the limit of a series is 0, it does not necessarily mean that series is converging.

Here, the limit of all 4 options is 0.  However, the fourth option is a diverging series.

What number must be added to the expression below to complete the square? x2+x

Answers

Answer:

answer is 1/4

Step-by-step explanation:

proof is (x-1/2)²= x²-2*1/2*x+1/4= x²-x+1/4

What is the value of 3x2 - 5xy + 5y2 for x = -6 and y = 2?

Answers

Answer is 188 3x2 - 5xy + 5y2 Now put x = -6 and y = 2 3(-6)2 - 5(-6)(2) + 5(2)2 3(36) - 5(-12) + 5(4) 108 + 60 + 20 188

PLEASE PLEASE HELP!! NO ONE IS ANSWERING!! this is geometry ://

Answers

Answer:

onse sec and ill help

Step-by-step explanation:

Line ET is tangent to circle A at T, and the measure of Arc TG is 70°.What is the measure of ∠GET?

A. 55°
B. 20°
C. 35°
D. 110°

Answers

Line ET is tangent to circle A at T

∴ ET ⊥ TN 
∴ ∠ ETN = 90
the measure of Arc TG = 70

∠ TNG = half the measure of Arc TG = 0.5 *70 = 35

Δ ETN ⇒ The sum of all angles = 180

∴∠ GET = ∠ NET = 180 - (90 + 35 ) = 55


∴ The correct answer is option A. 55°



I will calculate this problem in two ways

alternative method 1
we know that
The inscribed angle measures half of the arc it comprises.
∠TNE=(1/2)*arc TG------> (1/2)*70°----> 35°

the triangle TEN is a right triangle
∠TNE+∠GET=90°-----> by complementary angles
∠GET=90-35---> 55°

the answer is
∠GET=55°

alternative method 2
we know that
The measure of the external angle is the semi difference of the arcs that it covers.
∠GET=(1/2)*[arc TN-arc TG]---> (1/2)*[180-70]---> (1/2)*110---> 55°

the answer is
∠GET=55°


When competing for admission to more selective four-year colleges, which of the following can be just important as a GPA?. A. Letters of recommendation. B. Personal statement. C. Community & Extra curricular activities. D. High school class size

Answers

When competing for admission to more selective four year colleges, community and extra curricular activities are important as GPA.

What is GPA?

"A grade point average is a number representing the average value of the accumulated final grades earned in courses over time. More commonly called a GPA, a student’s grade point average is calculated by adding up all accumulated final grades and dividing that figure by the number of grades awarded. This calculation results in a mathematical mean—or average—of all final grades. The most common form of GPA is based on a 0 to 4.0 scale (A = 4.0, B = 3.0, C = 2.0, D = 1.0, and F = 0), with a 4.0 representing a “perfect” GPA—or a student having earned straight As in every course."

Extra curricular activities help developing inter personality traits like working in team and having coordination.

These all help us building and finding yourselves, this is the reason colleges and university focus on more extra curricular activities.

That is why extra curricular are as important as GPA.

Hence, C is the correct option.

To know more about GPA here

brainly.com/question/16980236

#SPJ3

Answer:

C

Step-by-step explanation:

A-P-E-X APPROVED