Answer:
? ≈ 24°
Step-by-step explanation:
using the sine ratio in the right triangle
sin? = = , then
? = ( ) ≈ 24° ( to the nearest degree )
-6
6
8
This should be the answer
Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5).
f(-2) = 3(-2) =-6 -1 = -7
g(5) = -(5) = -5 +6= 1
-7+1= -6
Answer: -6
interval <-1;1>, which means that this function can take values from interval <-7;-1>. The minimum value is -7.
the min of cos (5pi/6(x+4) = -1
so the min of 4cos 5pi/6(x+4 = -4
so the min of -3 + 4 cos 5pi/6(x+4 = -7
If the quadratic equation has a positive term, it also has a minimum value. This minimum can be found by graphing the function or by using one of the two equations. If you have an equation of the form y = ax ^ 2 + bx + c, you can use the equation min = c --b ^ 2 / 4a to find the minimum value.
Rearrange the function using basic algebraic rules and solve the value of x when the derivative is zero. This solution provides the x-coordinates of the vertices of the function where the maximum or minimum values occur. Convert to the original function and solve to find the minimum or maximum value.
Learn more about the function at
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Answer:
-7
Step-by-step explanation:
A P E X
B. 100
C. 125
D. 225
E. 12,500