College BoardThe number of hours of daylight, d, in Hartsville can be modeled by d = (35/3) + (7/3) (sin((2π/365)t)), where t is the number of days after March 21. The day with the greatest number of hours of daylight has how many more daylight hours than May 1? (March and May have 31 days each. April and June have 30 days each.)
A. 0.8 hr
B. 1.5 hr
C. 2.3 hr
D. 3.0 hr
E. 4.7 hr

Answers

Answer 1
Answer: Sincethis is an SAT Math Level 2 problem derivatives should not be requiredto find the solution. To find "How many more hours of daylight does theday with max sunlight have than May 1," all you need to understand isthat sin(x) has a maximum value of 1.

The day with max sunlight will occur when sin(2*pi*t/365) = 1, giving the max sunlight to be 35/3 + 7/3 = 14 hours

Evaluating your equation for sunlight when t = 41, May 1 will have about 13.18 hours of sunlight.

The difference is about 0.82 hours of sunlight.

Even though it is unnecessary for this problem, finding the actual maxsunlight day can be done by solving for t when d = 14, of by the use ofcalculus. Common min/max problems on the SAT Math Level 2 involve sinand cos, which both have min values of -1 and max values of 1, and alsopolynomial functions with only even powered variables or variableexpressions, which have a min/max when the variable or variableexpression equals 0.

For example, f(x) = (x-2)^4 + 4 will have a min value of 4 when x = 2. Hope this helps

Answer 2
Answer:

Final answer:

In Hartsville, the summer solstice has about 1.5 hours more daylight than May 1.

Explanation:

The problem requires calculating the difference in daylight hours between the day with the longest day (also known as the summer solstice) and May 1. The summer solstice is typically around June 21, which is 92 days after March 21. We can find the number of daylight hours on this day by substituting t = 92 into the formula: d = (35/3) + (7/3) (sin((2π/365)*92)). This equals about 16.2 hours.

Next, we find the number of daylight hours on May 1, which is 41 days after March 21, by substituting t = 41 into the formula: d = (35/3) + (7/3)(sin((2π/365)*41)), which equals approximately 14.7 hours.

Then, we find the difference between the two by subtracting the daylight hours on May 1 from the daylight hours on the summer solstice: 16.2 - 14.7 = 1.5 hours. Therefore, the summer solstice has 1.5 hours more daylight than May 1.

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Evaluate x²-6x when x=3-i.

Answers

Answer:

10

Step-by-step explanation:

We are going to substitute x = 3 - i into the expression x² - 6x

* Remember than i² = (√-1)² = -1. so when we multiply and get i² we're going to transform it into -1.*

x^2-6x = (3 - i)^2 - 6 (3-i) = 9 - 6i+i^2 -18+6i\n=9 - 6i-1-18+6i\n=-10

Thus, x² - 6x = 10 when x = 3-i

13.What is the circumference of a circle whose area is 16 pi?
A. 64 pi
B. 32 pi
C. 8 pi
D. 4 pi

Answers

I think it would be 4 po

Answer:

What is the circumference of a circle whose area is 16 π ?

A. 64  π  

B. 32 π  

C. 8  π  

D. 4  π

Step-by-step explanation:

its  8 π  cause it said it was correct

Convert 4 years to months​

Answers

Answer:

48 months

Step-by-step explanation:

12 times 4 48

Answer:

48 months

There's 12 months in 1 year.

So we would multiply 12 months by 4 years to get 48 months

Given linear function g(x) = 5 - 2/3 xa) find g(9)
AND
b) solve g(x)=7 for x

Answers

For part a, we need to substitute 9 for x.

g(x) = 5 - 2/3(9). Simplify the right side of the equation.

g(x) = 5 - 6.

g(x) = -1

For part b, we need to solve for x by substituting 7 for g(x).

7 = 5 - 2/3x. Subtract 5 from both sides.

2 = -2/3x. Divide each side by -2/3.

-3 = x

What is 8/16 in simplest form

Answers

1/2 is the simpliest form,divide everything by 2
Not really because 8 times something equals 16 so, 8x2=16
So your answer is two. 

Nells mortgage is 50,150 at 10 percent for 30 years. What is her monthly payment if she must pay 8.78 points per 1,000?A.) 440.32
B.) 439
C.) 422.95
D.) 385.89

Answers

I think it the answer is A.) 440.32

50,150 / 1,000 = 50.15 
50.15 x 8.78 = 440.317 or 440.32