In Hartsville, the summer solstice has about 1.5 hours more daylight than May 1.
The problem requires calculating the difference in daylight hours between the day with the longest day (also known as the summer solstice) and May 1. The summer solstice is typically around June 21, which is 92 days after March 21. We can find the number of daylight hours on this day by substituting t = 92 into the formula: d = (35/3) + (7/3) (sin((2π/365)*92)). This equals about 16.2 hours.
Next, we find the number of daylight hours on May 1, which is 41 days after March 21, by substituting t = 41 into the formula: d = (35/3) + (7/3)(sin((2π/365)*41)), which equals approximately 14.7 hours.
Then, we find the difference between the two by subtracting the daylight hours on May 1 from the daylight hours on the summer solstice: 16.2 - 14.7 = 1.5 hours. Therefore, the summer solstice has 1.5 hours more daylight than May 1.
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Answer:
10
Step-by-step explanation:
We are going to substitute x = 3 - i into the expression x² - 6x
* Remember than i² = (√-1)² = -1. so when we multiply and get i² we're going to transform it into -1.*
⇒
Thus, x² - 6x = 10 when x = 3-i
A. 64 pi
B. 32 pi
C. 8 pi
D. 4 pi
Answer:
What is the circumference of a circle whose area is 16 π ?
A. 64 π
B. 32 π
C. 8 π
D. 4 π
Step-by-step explanation:
its 8 π cause it said it was correct
Answer:
48 months
Step-by-step explanation:
12 times 4 48
Answer:
48 months
There's 12 months in 1 year.
So we would multiply 12 months by 4 years to get 48 months
AND
b) solve g(x)=7 for x
For part a, we need to substitute 9 for x.
g(x) = 5 - 2/3(9). Simplify the right side of the equation.
g(x) = 5 - 6.
g(x) = -1
For part b, we need to solve for x by substituting 7 for g(x).
7 = 5 - 2/3x. Subtract 5 from both sides.
2 = -2/3x. Divide each side by -2/3.
-3 = x
B.) 439
C.) 422.95
D.) 385.89