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Answer:
d) 2/3
Step-by-step explanation:
Step one: write your equations
"A student spends no more than 2 hours on his math and English homework." Our sign will be less than or equal to. Our operation will be addition since the question used "and" to connect math and English.
m=x; e=y
Equation a. x + y ≤ 2
Equation b. x = 2y (2y because math takes twice as long, therefore, we can multiply y by 2) Remember: x or y by itself has a coefficient of 1.
Step two: Substitute x into equation a.
x=2y so our new equation is: 2y + y ≤ 2
Step three: isolate y and solve
2y + y= 3y
3y ≤ 2
Next, isolate y by dividing both sides by 3.
3y/3 ≤ 2/3
y ≤ 2/3
There is your answer, English equals y, so the maximum time he can take on his English work is 2/3 of an hour or 40 minutes.
Full question: A student spends no more than 2 hours on his math and English homework. If math takes about twice as long as English, what is the maximum time that the student can spend on English?
Answer:
For each of the three basic trig functions, (sin, cos, tan) there are three more which act as their reciprocals. (csc, sec, and cot respectively)
Reciprocals, of course, are flipped fractions. If you have some number x, the reciprocal can be expressed as .
An important property of reciprocals is that if you mutliply them together they will cancel out--take for example.
Since secӨ is literally defined as the reciprocal of cosӨ, it is evident that
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Step-by-step explanation:
Answer:
720
Step-by-step explanation: