When you align a table in relation to the content around it, the table's cells will be positioned in accordance with the alignmentchoice (e.g., left, center, or right) but the cells themselves remain unchanged.
Aligning a table in relation to the content around it primarily affects the positioning of the table as a whole. The table's cells, which are the individual rectangular areas within the table, maintain their structure, dimensions, and content. The alignment choice (e.g., left, center, or right) determines where the entire table is placed in relation to the surrounding text or elements on the page. This can be useful for layout purposes, ensuring that the table fits well within the document, but it does not alter the properties or content of the cells themselves.
In summary, when aligning a table, the cells within the table remain unaltered, with alignment affecting the positioning of the entire table on the page.
Learn more about table alignment here:
#SPJ11
Answer:
They keep the alignment they already had.
Explanation:
B. ask fewer than 20 questions.
C. connect it to some cause they're interested in.
D. offer a discount coupon to the first 100 who return it.
A. print a bold deadline at the top.
B. ask fewer than 20 questions.
C. connect it to some cause they're interested in.
D. offer a discount coupon to the first 100 who return it.
An effective way to encourage people to return a mail questionnaire quickly is to print a bold deadline at the top. The answer is letter A.
The correct option is D. offer a discount coupon to the first 100 who return it.
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int x=5,y=2,z=9;
int min;
// find the smallest value and assign to min
// if x is smallest
if(x < y && x < z)
// assign x to min
min=x;
// if y is smallest
else if(y < z)
// assign y to min
min=y;
// if z is smallest
else
// assign z to min
min=z;
// print the smallest
cout<<"smallest value is:"<<min<<endl;
return 0;
}
Explanation:
Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".
Output:
smallest value is:2