Find the distance between the two points in simplest radical form. The points given are (1,8) and (6,-4).​

Answers

Answer 1
Answer:

Answer:

d = 13 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }

let (x₁, y₁ ) = (1, 8 ) and (x₂, y₂ ) = (6, - 4 )

substitute these values into the formula for d

d = √((6-1)^2+(-4-8)^2)

  = √(5^2+(-12)^2)

  = √(25+144)

  = √(169)

  = 13 units


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Which equation is true when b = -4?A b/4 + 5.5 = 4.5
B -54 + 2b = -46
С 7b - 8 = -20
D b/8 - 6 = -8

Answers

Answer:

A

Step-by-step explanation:

-4/4 = -1

-1+5.5

=4.5

The answer is B. -54+2b=-46

Graph the parabola. y=x^2 -4 where do i put the points

Answers

To generate a point, you plug in a number for x to get the corresponding y value.

If x = 0 for instance, then the y value is...

y = x^2 - 4

y = 0^2 - 4 ... x is replaced with 0

y = 0 - 4

y = -4

So x = 0 and y = -4 pair up to get the point (0,-4). This is the y intercept as the parabola crosses the y axis here. It turns out that this is also the vertex point as it is the lowest point on the parabola.

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If x = 1, then,

y = x^2 - 4

y = 1^2 - 4

y = 1 - 4

y = -3

meaning (x,y) = (1,-3) is another point on this line.

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Repeat for x = 2

y = x^2 - 4

y = 2^2 - 4

y = 4-4

y = 0

Since we got a y output of 0, we have found an x intercept located at (2,0). The other x intercept is (-2,0).

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The idea is to generate as many points as possible. Plot all of the points on the same xy coordinate grid. Then draw a curve through those points the best you can. You should get what you see in the diagram below. I used GeoGebra to make the graph. Desmos is another handy tool I recommend.

Note: the more points you generate, the more accurate the graph will be

Y = 3x + 4y, x + 2y = -1 using substitution

Answers

Answer:

x = 1

y = -1

Step-by-step explanation:

y = 3x + 4y

3x + 3y = 0

So, we have 2 equations that are

3x + 3y = 0

x + 2y = -1

Times the second equation by -3

3x + 3y = 0

-3x - 6y = 3

-3y = 3

y = -1

Now put -1 in for y and solve for x

x + 2(-1) = -1

x - 2 = -1

x = 1

Let's check

1 + 2(-1) = -1

1 - 2 = -1

-1 = -1

So, x = 1 and y = -1 is the correct answer.

The answers should be x=1 and y=-1

If (x2 +3x +5)(x2 +3x - 5) = m2-n2, then find m ?

Answers

(x^2+3x+5)(x^2+3x-5)=m^2-n^2\n\n\ [(x^2+3x)+5][(x^2+3x)-5]=(m+n)(m-n)\n\nm=x^2+3x;\ n=5

2^1-x=3^2x-3 solve for X

Answers

Hello,

if the exact equation is

2^(1-x)=3^(2x-3)

==>(1-x)ln 2=(2x-3) ln 3

==>2x ln 3+x ln 2=ln 2 +3 ln 3

==>x=ln (2*3^3) / ln (2*3²)

==> x= ln(54)/ ln (18)

==>x ≈1,3800937....


if the equation is 2^1 -x  =3^2 *x -3 then

2-x=9x-3
==>10x=5
==>x=1/2





A test has multiple choice questions with 5 choices for each answer; only one answer is correct for each question. Suppose a student guesses the answer to each question. Assuming the guesses are independent, find the probability that the student will not guess correctly on any one question.

Answers

First you have to define perimeters of Binomial distribution.

n - how many trials/questions do you have
p - probability guessing right answer to each question
x - how many successes do you expect.
Assuming the 6 questions are independent,
n=6 (questions)
p=probability of guessing the right answer (1/5)
x=exactly the number of successes over the 6 questions (2).

Look up the appendix table, or the Excel function to calculate the probability.