Blossom Marine Products began the year with 10 units of marine floats at a cost of $12 each. During the year, it made the following purchases: May 5, 27 units at $16; July 16, 19 units at $20; and December 7, 24 units at $23. Assume there are 29 units on hand at the end of the period. Blossom uses the periodic system.

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Write a subtraction problem with a difference of -2, where both numbers are negative.
Let θ be an acute angle such that cosθ = 1/3. Find the value of tanθ.
Write an equation for each condition 1) The line with a slope of 7 and a y-intercept of -1( in slope-intercept form) 2) The line that passes through (1,-5) and has a slope of 3 (in point-slope form)

Need help. 35-(-55)=?

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the answer is 90.Remember that whenever you see two - signs right next to eachother it turns into an addition sign

Remember that subtracting a negative number is the same as adding a positive number.(two negatives equals a positive) For example:

35-(-55)=35+55

They are both equivalent. Now we can solve..

35+55=90

Answer=90

One-half of a number is 1 more than one-third of the same number. What is the number?

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Let the number be x,
(1/2)x=1+(1/3)x
Solving for x,
(1/2)x-(1/3)x=1+(1/3)x-(1/3)x
(1/2)x-(1/3)x=1
(1*3/6)x-(1*2/6)x=1
(3/6)x-(2/6)x=1
(1/6)x=1
6*(1/6)x=6*1
Therefore, x=6

(1/2)x = (1/3)x +1
-(1/3)x -(1/3)x

(1/6)x=1
*6 *6
x=6

And so x=6, or your number is 6

A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would be defective. With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

Answers

Answer: 216

Step-by-step explanation:

The formula to find the sample size , if prior population proportion is known :-

$n=p(1-p)((z_(\alpha/2))/(E))^2$

Given : The prior proportion of defective parts : p= 0.10

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_(\alpha/2)=1.96$

Margin of error : $E=0.04$

Now, the required sample size will be :-

$n=0.1(0.9)(((1.96))/(0.04))^2=216.09\approx216$

Hence, the minimum required sample size = 216

Final answer:

To achieve a margin of error of .04 or less with a 95% confidence level when the defect rate is 10%, at least 217 samples need to be taken.

Explanation:

The question pertains to the field of statistics, specifically sample sizes and margin of error. In order to estimate the minimum sample size needed to achieve a desired margin of error of .04 or less, we can use the formula for sample size in proportions: n = (Z^2*p*(1-p))/E^2.

In this formula:

Z refers to the z-value which, for a 95% confidence level, is 1.96.
p is the estimated proportion of defective parts, which in this case is 0.1 or 10%.
E is the desired margin of error, which is 0.04.

Substitute the values into the formula: n = (1.96^2*0.1*0.9)/(0.04^2), yielding n=216.09.

Since we can't have a fraction of a sample, we round up to get n = 217. Therefore, we need a sample size of 217 to reach a margin of error of .04 or less with a 95% confidence level.

Learn more about Sample Size Calculation here:

brainly.com/question/34288377

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A student got an 85% on his test . If he got 12 questions wrong , how many questions were on the test?

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Answer:

80 questions

Step-by-step explanation:

Given that a student received an 85% grade on his test, and that he got 12 questions wrong:

We could infer that if he answered all of the test questions correctly, then he would have received a perfect score of 100% on his test.

Since he got 12 questions wrong, then it means that those wrong answers account for the 15% out of receiving a 100% grade on his test (or: 100% - 85% = 15%).

Let x = number of test questions

In order to find how many questions were on his test:

12 questions = 15% (or 0.15) of the total number of questions (x)

12 questions = 0.15x

Divide both sides by 0.15 to isolate x:

$\displaystyle\mathsf{(12\:questions)/(0.15)\:=\:(0.15x)/(0.15)}$

x = 80 questions

Therefore, there were 80 questions on his test.

1-4x = 3-4y___ ____
2+x y

if y is a non zero constant, which equation represents the value of x in the given equation?
A) x=3y-2
B)x=3y+2
C)x=9y-6
D)x=9y+6

I have no idea how to solve.

Answers

the answer is A
x=3y-2
see photo attached

The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend? The choices are: A. 6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8 B. 6d5 – 4c3d2 + 3c2d3 – 4cd4 + 8 C. 6d5 – 4c3d2 + 5c2d3 – 12cd4 + 8 D. 6d5 – 2c3d2 – 3c2d3 – 4cd4 + 8