75% of a number is 120. what is 40% of the number?

Answers

Answer 1
Answer: 75%= 3/4
120*4=480
480/3=160
160/10=16
16*4=64
Hope you understand it

Related Questions

If you can, please help
List three multiples of 9.
A chef cooked seven kilograms of mashed potatoes for a dinnerparty. If the guests only ate three-quarters of the amount he cooked,how much did they eat?.....................plz hurry up
For what value of n is -5n = 7-5(n-5)-32
In the number 284,which dight is in the hund place?

Which equation represents an exponential function that passes through the point (2, 36)?A.f(x) = 4(3)x
B.f(x) = 4(x)3
C.f(x) = 6(3)x
D.f(x) = 6(x)3

Answers

Hello,
A) 4*3^2=4*9=36
Others: 32,54,48

Y is direcly proportional to x and y=27 when x=6find x when y=45

Answers

Answer:

x= 10

Step-by-step explanation:

27÷6= 4.5

27×4.5= 6

so,

45÷4.5=10

Answer:

7.5

Step-by-step explanation:

45 divided by 6 i don't know but I just wanted to try

If it costs $3 per hour to park in a parking lot, with a maximum cost of $12 Explain why the amount of time a car is parked is not a function of the parking cost

Answers

The cost of parking in a lot can be calculated as; Cost = cost rate x time. Let the time = t. When time, t = 1 hour, Cost = 3 x 1 = $3. When time, t = 2 hours, Cost = 3 x 2 = $6. When time, t = 3 hours, Cost = 3 x 3 = $9. When time, t = 4 hours, Cost = 3 x 4 = $12. When time, t = 5, Cost = 3 x 5 = $15 (notice, $15 has exceeded $12, but the maximum cost has to be $12). Thus, the cost of parking in a lot depends on the amount of time the car is parked and not vice versa. Therefore, the amount of time a car is parked is not a function of the parking cost because time is an independent variable and the cost of parking depends on the time the car is parked

The Bimini High School rugby team won the state championship in 2014. Arecord of their wins and losses is shown, in which the relationship between wins
and losses is sorted by number of points scored.
> 40 points <40 points Total
Win 18
11
29
Loss 2
9
11
Total 20
20
40
Which of the following is the best evidence of an association between scoring
40 points or more and the rugby team winning a game?

Answers

The best evidence is given when scoring 40 points or more in a game, the Bimini team won more games (18/20) than when scoring fewer than 40 points (11/20).

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
The rugby squad from Bimini High School won the state title that year. A record of their wins and losses is shown, in which the relationship between wins and losses is sorted by the number of points scored. From observation, The best evidence is given when scoring 40 points or more in a game, the Bimini team won more games (18/20) than when scoring fewer than 40 points (11/20).

Thus, the best evidence is given when scoring 40 points or more in a game, the Bimini team won more games (18/20) than when scoring fewer than 40 points (11/20).

Learn more about simplification here:
brainly.com/question/12501526

#SPJ2

Answer:

The Bimini team won a high proportion of games when scoring 40 points or more (18/20) compared with when they scored less than 40 points (11/20).

Pls complete it (picture)​

Answers

Answer:

1. Perimeter: 26 Area: 30

2. Perimeter: 20 Area: 25

3. Perimeter: 38 Area: 144

Step-by-step explanation:

Perimeter you add all the sides and area you multiply length times height.

. Out of 140 students, 50 passed in English and 20 passed in both Nepali and English. The number of students who passed in Nepali is twice the number of students who passed in English. Using a Venn-diagram, find the number of students who passed in Nepali only and who didn't pass in both subjects. ​

Answers

Answer:

80 ;

10

Step-by-step explanation:

Given :

Total number of students = μ = 140

Let :

Number of students who passed in English = E

Number of students who passed in Nepali = N

n(NnE) = 20

n(E) only = n(E) - n(NnE) = 50 - 20 = 30

Students who passed English only = 30

Number of students who passed in Nepali is twice the number who passed in English

n(N) = 2 * n(E) = 2 * 50 = 100

Number of students who passed in Nepali only

n(N) only = n(N) - n(NnE) = 100 - 20 = 80

Students who passed Nepali only = 80

The number who didn't pass both subjects :

μ - (English only + Nepali only + English and Nepali)

140 - (30 + 80 + 20)

140 - 130

= 10