MATHEMATICS HIGH SCHOOL

Solve with completing the square method:
6x²-7x+2=0 and  ax²+bx+c=0

Answers

Answer 1
Answer: 6x ^2-7x+2=0\n \n a=6 , \ b = -7 , \ c=2 \n \n\Delta = b^(2)-4ac = (-7)^(2)-4*6*2=49-48=1 \n \nx_(1)=(-b-√(\Delta ))/(2a) =(7-√(1))/(2*6)=(7-1)/(12) =(6)/(12)= (1)/( 2)\n \nx_(2)=(-b+√(\Delta ))/(2a) =(7+√(1))/(2*6)=(7+1)/(12) =(8)/(12)= (2)/( 3)

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Help mee please i don’t understand

Answers

The answers in order is
Bc
Dc
Sas

What is 1 7/9 - 4/9?Express the answer in simplest form
What is ?



Express the answer in simplest form
what is 2 5/12 -(-2 1/6)

Answers

1 7/9 - 4/9

Convert 1 7/9 to an improper fraction:

16/9 - 4/9

Subtract the numerators together:

12/9

Convert to a whole number:

1 1/3
The answer is 1 3/9 which turns in to 1 1/3

The force of an object (f) is equal to its mass (m) times its acceleration (a). Thus, the formula for calculating force is f = ma. Based on this information, which of the following equations would be used to calculate acceleration?A. a = f ÷ m
B. a = f − m
C. a = f + m
D. a = fm

Answers

The correct answer is A. To rearrange the equation, you have to divide both sides by "m" to isolate "a" so that acceleration can be directly calculated. This would result in the equation becoming: f/m = ma/m As the mass (m) on the right hand side of the equation appears in the numerator and the denominator, it can be cancelled, resulting in the new equation: f/m = a which can then be flipped to give a = f/m.

Can someone help please!!!!!

Answers

Answer:

x

{x}^(2) - 3

An airplane pilot fell 370 m after jumping without his parachute opening. He landed in a snowbank, creating a crater 1.5 m deep, but survived with only minor injuries. Assume that the pilot's mass was 84 kg and his terminal velocity was 50 m/s.estimate

Answers

Answer:

he ded

Step-by-step explanation:

\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \tohe no alive  because ⇆ω⇆π⊂∴∨α∈\neq  \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_(n \to \infty) a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_(n \to \infty) a_n \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \beta x_{12 \lim_{n \to

Which of the following shows the correct factorization of x3 - 5x2 - 14x?A. x(x + 7)(x + 2)

B. x(x - 7)(x - 2)

C. x(x + 7)(x - 2)

D. x(x - 7)(x + 2)

Answers

So, just a note of formatting, to indicate something is an exponent of something else, use the carat (^) sign 
for instance
x^3 means x cubed. x3 means 3x.
Anyways, though, let's factor.
You can factor out an x from each variable.
x(x^2-5x-14)
Now, to factor this, think of what will add to -5, and multiply to -14.
-7 and 2 work.
So, this factors out to
x(x-7)(x+2)
Choice D is the correct factorization.
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