Log4(x)+log4(x+15)=2

Answers

Answer 1
Answer: D:x>0 \wedge x+15>0\nD:x>0 \wedge x>-15\nD:x>0\n\n\log_4x+\log_4(x+15)=2\n\log_4x(x+15)=2\n4^2=x(x+15)\n16=x^2+15x\nx^2+15x-16=0\nx^2-x+16x-16=0\nx(x-1)+16(x-1)=0\n(x+16)(x-1)=0\nx=-16 \vee x=1\n-16\not \in D \Rightarrow \boxed{x=1}
Answer 2
Answer: Log4(x)+log4(x+15)=2
x>0;
x+15>0 => x>0
Log4(x)+log4(x+15)=2
Log4(x*(x+15))=Log4(16)x*(x+15)=16 
x1=1
x2=-16 
 х=1

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Suppose you produce a camera that costs $50 to make. At a selling price of $45, you will _____.earn a profit
just cover your costs
lose money

Answers

Answer:

You will __$5___earn a profit  just cover your costs  lose money

Step-by-step explanation:

As per the statement:

Cost Price of the camera = $50  

Selling price of the camera = $45

We have to find the profit that you will earn.

Since,  C.P > S.P then, you have suffer a loss.

Using formula:

\text{Loss} = \text{Cost Price} -\text{Selling price}

Then;

\text{Loss} = 50-45 = \$5

Thus, if you want to cover your costs lose money , then you will earn a profit of $5

You will lose money. Because $50 to make subtract $45 to sell (50-45) leaves you losing $5.

Help asap pls !!! I am stuck for like 15 mins

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