SOLVE BY SUBSTITUTION:3x-2y=14
y=5x
solve by substitution
x-2y=-2
y=2x+4
solve by elimination
x+2y=-7
x-5y=7
PLEASE HELP WORTH 10 POINTS! AKA SHOW WORK:)

Answers

Answer 1

Answer: 1)
3x-2y=14
y=5x

So we plug in y=5x into 3x-2y=14

We get:

3x-2(5x)=14
3x -10x=14
-7x=14
x=-2

So we found x, now we need to find y. We can simply plug in x into the equation and get y.

y=5x
y=5(-2)
y=-10

So your answer will be (-2,-10).

2)
x-2y= -2
y= 2x+4

Once again plug in y=2x+4 into x-2y=-2

x-2(2x+4) = -2
x-4x-8=-2
-3x-8=-2
-3x = 6
x= -2

Now we plug back in x and solve for y :)

y=2x+4
y=2(-2)+4
y=-4+4
y=0

So our solution would be (-2,0).

3)
x+2y=-7
x-5y=7

Multiply the second equation by -1

-x+5y=-7

Now add that equation with the other one:

x+2y=-7
+
-x+5y=-7
-----------------
7y=-14
y=-2

Now plug in y=-2 and solve for x

x+2y=-7
x+2(-2)=-7
x+(-4)=-7
x-4=-7
x=-3

So your solution would be (-3,-2).

Answer 2

Answer: 1)

$3x-2y=14\n \n y=5x$

We know y's value. Let's plug it in the equation.

$y=5x\n \n 3x-2\cdot (5x)=14\n \n 3x-10x=14\n \n -7x=14$

Divide both sides by -7.

$x=-2$

Now we have x's value. Let's plug it in the equation to find y.

$x=-2\n \n y=5x\n \n y=5\cdot -2\n \n y=-10$

Solution,

(-2, -10)

2)
$x-2y=-2\n \n y=2x+4$

Again we have y's value. Let's plug and solve.

$y=2x+4\n \n x-2\cdot (2x+4)=-2\n \n x-(2\cdot 2x+2\cdot 4)=-2\n \n x-4x-8=-2\n \n -3x-8=-2\n \n -3x=-2+8\n \n -3x=6\n \n x=\frac { 6 }{ -3 } \n \n x=-2$

Now we have x's value let's solve for y.

$x=-2\n \n y=2x+4\n \n y=2\cdot (-2)+4\n \n y=-4+4\n \n y=0$

Solution,

(-2, 0)

3)

$x+2y=-7\n \n x-5y=7$

Let's first multiply the first equation by -1

$-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7$

Then let's add these new equation and the second equation.

$-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7\n \n x-5y=7\n \n (-x-2y)+(x-5y)=7+7\n \n -x+x-2y-5y=14\n \n -7y=14\n \n y=\frac { 14 }{ -7 } \n \n y=-2$

Now we have y's value let's plug it and solve for x.

$y=-2\n \n x+2y=-7\n \n x+2\cdot (-2)=-7\n \n x-4=-7\n \n x=-7+4\n \n x=-3$

Solution,

(-3, -2)

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Can someone answer this question please answer it correctly if it’s correct I will mark you brainliest

Answers

First, let's find the area of the patio:

6.25 * 6.25 = 39.0625

Next, we need to find the area of the patio and extension combined:

We know that the patio is now 3m wider and 1.5m longer.

(6.25 + 3) * (6.25 + 1.5)

9.25 * 7.75 = 71.6825

Then, we need to find the area of the extension alone, which can be done by subtracting the area of the patio from the area of the patio and extension combined:

71.6825 - 39.0625 = 32.625

Now, find the area of one tile:

0.25 * 0.25 = 0.0625

And divide the area of the extension by the area of one tile to find the number of tiles needed to build the extension:

32.625 / 0.0625 = 522

Divide the total number of tiles by 25 and round up to the nearest whole number to find the number of packages:

522 / 25 = 20.88

20.88 rounds up to 21 packages of tiles.

Ellis needs 21 packages of tiles.

Hope this helps!! :)

Answer:

Step-by-step explanation:

Area to be covered:

(6.25 + 1.5)(6.25 + 2(1.5)) - 6.25²

= 32.625

Each title's area = 0.25² = 0.0625

No. of tiles needed:

32.625 ÷ 0.0625

= 522

25 in each pack

522/25 = 20.88

So 21 packets

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Answers

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Answers

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