PHYSICS HIGH SCHOOL

Explain why it’s hurt more carrying a heavy bag with a string of wire

Answers

Answer 1
Answer:

Explanation:

Carrying a heavy bag with a string of wire can cause more pain compared to carrying a bag without a string of wire due to a few reasons.

Firstly, the presence of the string of wire adds additional pressure and strain on your hand, making it harder to grip and carry the bag comfortably. The wire can dig into your skin and cause discomfort or even pain. Imagine holding a bag with a smooth handle versus holding a bag with a sharp wire cutting into your hand - the latter would definitely be more painful.

Secondly, the wire can create friction against your skin. As you carry the bag and walk, the movement can cause the wire to rub against your hand, resulting in irritation and potentially even blisters. This friction can also cause the wire to dig deeper into your skin, intensifying the pain.

Lastly, the weight distribution of the bag can be affected by the presence of the wire. When you carry a heavy bag, it is ideal for the weight to be evenly distributed to minimize strain on specific areas of your body. However, the wire can create an uneven distribution of weight within the bag. This can lead to increased pressure and discomfort on certain parts of your hand, making it more painful to carry the bag.

In summary, carrying a heavy bag with a string of wire can hurt more due to the additional pressure and strain on your hand, the friction caused by the wire rubbing against your skin, and the uneven weight distribution within the bag. It is important to consider these factors when carrying heavy objects to minimize discomfort and potential injury.

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A car travels 1000 meters in 5 seconds. What is its average velocity?

Answers

Answer:

the velocity is 200

Explanation:
the average velocity is 200

A system is best described as: a. a form of energy that is transferred between two substances at different temperatures. b. mass that assumes a physical shape and occupies space. c. any set of ordered, interrelated components working as a unified whole. d. the capacity to change the motion of, or to do work on, matter. e. the point at which characteristics can no longer be maintained and a new state is adopted.

Answers

I think d sorry if it doesn’t help

The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 grams. The velocity of the stone when it reached the target was 15.0 meters/second. What was the value of the kinetic energy of the stone when it reached the target?

Answers

Answer: 2.25 J

Explanation: Kinetic energy is the energy possessed by an object by virtue of its motion.

K.E=(1)/(2)* mv^2

m= mass of object= 20 g = 0.02 kg     (1 kg= 1000 g)

v= velocity of object= 15 m/s

K.E=(1)/(2)* 0.02* 15^2=2.25kgm^2s^(-2)=2.25J

(1J=1kgm^2s^(-2))

1,000 grams = 1 kilogram
20 grams = 0.02 kilogram

Kinetic energy = (1/2) (mass) x (speed)²

                           (1/2) (0.02) x (15)² =

                                 (0.01)  x  (225)  =  2.25 joules
 

What is the most common state of matter in the universe

Answers

Answer:

Plasma

Explanation:

Plasmais the most common because plasma is a gas that has been energized to the point that some of the electrons break

A bear is sitting at rest on a tricycle. The bear then starts to accelerate uniformly at a rate of 2.5 m/s2 (meters per second square). How long will it take the bear to reach a velocity of 15 m/s (meters per second)

Answers

Answer:

6.0 s

Explanation:

Given:

u = 0 m/s

v = 15 m/s

a = 2.5 m/s²

Find: t

v = u + at

15 = 0 + (2.5) t

t = 6.0 s

A ball is thrown into the air and caught at the exact same distance from the ground. At what point is the ball's kinetic energy the greatest? Include air friction in your consideration.A.just before it is caughtB.at the highest point of its pathC.the instant it leaves the thrower's handD.halfway between where it is thrown and the highest point

Answers

Remember that the ball can never have MORE energy than you give it
when you toss it. 

You give the ball kinetic energy.  As it goes up, the kinetic energy
changes to potential energy, and on the way down, that potential
energy changes back into kinetic energy. 

If there's nothing along the way to steal any energy from the ball,
then its TOTAL energy (kinetic PLUS potential) is constant all the
way up and down.

But in this question, there IS something else in the picture, and it
steals energy from the ball.  Air resistance is partly the friction of
the air molecules scraping against the ball, and partly the work
that the ball has to do in order to push air out of the way so that
it can get through.  All of that steals energy whenever the ball is
moving.

So figure it out:  If you give it some energy when you throw it,
and it can never have any more than that because it doesn't
have little jet engines on it, and the air is constantly robbing
some of the energy whenever the ball is moving, then the most
it can ever have is just as it leaves your hand.
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