MATHEMATICS HIGH SCHOOL

Express in simplest radical form.
-√63 x^7 - 4x√7x^5

Answers

Answer 1

Answer:

Answer:

-21x^12

Step-by-step explanation:

To express the given expression in simplest radical form, let's simplify each term separately.

Starting with the first term, -√63x^7, we can simplify the square root of 63.

The prime factorization of 63 is 3 × 3 × 7. Since there is no perfect square factor, we can't simplify the square root any further. So, we have -√(3 × 3 × 7) x^7.

Now, let's move on to the second term, -4x√7x^5. We can simplify the square root of 7.

Since 7 is a prime number, there is no perfect square factor. So, we have -4x√7 x x^5.

Now, let's multiply the two terms together. Multiplying the numbers outside the radicals gives us -√(3 × 3 × 7) x^7 × -4x√7 x x^5.

Multiplying the x's together gives us x^7 x x^5 = x^(7+5) = x^12.

Multiplying the numbers under the radicals together gives us √(3 × 3 × 7) x √7 = √(3^2 x 7) x √7 = 3√7 x √7 = 3 x 7 = 21.

Combining these results, we have -21x^12.

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Both circle A and circle B have a central angle measuring 135°. The ratio of the radius of circle A to the radius of circle B is 4/7. If the length of the intercepted arc for circle A is 1/2π, what is the length of the intercepted arc for circle B?
Ozzie is 6 years older than McKenzie. Theo is Ozzie's dad and is 3 times older than McKenzie. Ozzie is 8 years old. How old is Theo?

Divide £10.00 into the ratio of 2:3

Answers

2+3=5
10.00/5=2
2 per unit
2 unit:3unit
2 times 2=4
2 times 3=6

2:3

4:6

Which function represents exponential growth?A. Y=35(1.35)^x
B. Y=35(0.35)^x
C. Y%35/1.35^x
D. Y%35x^1.35

Answers

Answer:

A. Y=35(1.35)^x

Step-by-step explanation:

Find the function that represents expontial growth

Exponential function is in the form of y=ab^x

When the value of b is >1 then it represents exponential growth

When the value of b is <1 then it represents exponential decay

In this exponential function Y=35(1.35)^x

The value of b is 1.35

the b value is greater than 1 so it is an exponential growth equation.

THERE ARE A NUMBER of students SITTING IN Acircle. They ARE EVENly spaced and the 7th
STUDENT IS SEATED directly ACROSS FROM THE
18th student
How many students are there altogether

Answers

Answer:

7x18=x

solve for x , X= 127

answer = there are 127 students all together

hope this helpes

Mabel measured an angle on her math worksheet with her protractor. The angle measured 39°. If she were to draw an angle which was supplementary to the angle on her worksheet, what should that new angle measure? A. 141° B. 51° C. 129°

Answers

The angle supplementary to the angle 39° Mabel measured is C. 129°.

What are supplementary and complementary angles?

When the sum of the two angles is 180° they are said to be supplementary.

When the sum of the two angles is 90° they are said to be complementary.

Given, Mabel measured an angle on her math worksheet with her protractor. The angle measured 39°.

Therefore, The angle supplementary to the angle she measured is,

= (180 - 39)°.

= 129°, As the sum if the sum of two angles are supplementary their sum is

180°.

learn more about supplementary angles here :

brainly.com/question/25251757

#SPJ2

Supplementary means to be equal to 180 degrees.

180 - 39 = 141

The answer is A. 141 degrees.

suppose there is a pile of quarters, dimes and pennies with a total value of $1.07. How much of each coin can be present without being able to make change for a dollar?

Answers

Hello,

In the triplet below (x,y,z) x is the number of quaters,
y the number of dimes,
z the number of pennies

Answer is : ( 1, 8, 2),( 3, 3, 2)

I107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

3. Suppose you invest $5,000 in a continuously compounded interest account. After four years,your account balance was $6,230. What interest rate were you earning on this account?
Convert your answer to percent and round your answer to the nearest tenth(one decimal
place).