Answer:
Therefore, the cost of purchasing 5 lip glosses, as represented by the function C(5), is 41.
Step-by-step explanation:
To find the cost of purchasing 5 lip glosses, we need to use the given function C(1) = 31 + 2, which represents the cost of ordering one lip gloss including the flat rate shipping charge. To find the cost of purchasing 5 lip glosses, we can substitute 5 for the variable in the function: C(5) = 31 + 2 * 5 C(5) = 31 + 10 C(5) = 41
The cost of purchasing 5 lip glosses represented in the function C(1)=31+2 is evaluated as C(5)=31+2*5, which equals 41 units.
This question involves the mathematical concept of functions, specifically, simple linear functions. In this example, we have the function C(1)=31+2, which informs us that the cost to order one lip gloss, denoted as 'L', is '31 plus twice the number of lip glosses ordered'
To answer the question 'What represents the cost of purchasing 5 lip glosses?', we substitute the number of lip glosses we want to buy (5) into our function. So instead of evaluating C(1), we evaluate C(5)=31+2*5, following the same structure of '31 plus twice the number of lip glosses ordered'. The solution to this would be C(5)=41, meaning it would cost 41 units (the currency isn't stated) for 5 lip glosses.
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Answer:
At t = 3, pilot can hit the target located at the origin.
Step-by-step explanation:
We have been given displacement vector:
r(t) = 5 - t, 21 - t², 3-t³/27
so, in this case r(t) and r'(t) should be in the parallel but opposite direction.
In order to get r'(t) we need to differentiate r(t).
r(t) = 5 - t, 21 - t², 3-t³/27
r'(t) = -1, -2t, -t²/9
Now perform the cross product among these two r(t) and r'(t).
r'(t) x r(t) =
= i ((-6t + )+ ( - )) -j ((-3 + + - )) + k ((-21 + + 10t -2))
= ( + - 6t )i + ( - +3) j + (-t² + 10t -21)k
In order to find the value of t, we need to put
+ - 6t = 0
-t² + 10t -21 = 0
So, after solving for t, we will get
- ( t-3) (t-7) = 0
t = 3 or t = 7
In this case, only t = 3 satisfies the other two equations as well. t=7 is not satisfying. So take t =3 as the time. and for further assurance, we need to check are our vectors r(t) and r'(t) opposite at t = 3 or not. Let's check it out.
r(3) = 5-3, 21 - 3², 3 - 3³/27
r (3) = 2, 12, 2
r'(3) = -1, -2(3) , -3²/9
r'(3) = -1, -6 -1
Here, we can easily see that, r(3) = -2 r'(3) which is opposite and hence it is proved that, at exactly t = 3, pilot can hit a target located at the origin.
Answer:
the largest is:
Step-by-step explanation:
We are given the expression C>D>0.
As C and D represent two different school populations. This means that C and D will be natural numbers.
C+D<2×(C+D)
Also .
the largest among these expressions is
if n is a positive integer, for what values of n is the function f(x) =x to the power of n a) even b) odd
Answer:
Step-by-step explanation:
Givens
P = 2*L + 2*W
P = 70
w = 16
Solution
70 = 2L + 2*16
70 = 2L + 32
70-32 = 2L
38 = 2L
38/2 = 2L/2
L = 19