Jut for every answer choose negative or poitive1.(–21.9) • (–6) • (–1.1) • (–0.47)
a. negative b. positive

2. (–39) • (0.5) • (–0.92) • (6.1) • (–12
a. negative b. positive 3.
(0.01) • (–43) • (7.2) • (–86)
a. negative b. positive 4.(–3.5) • (–16) • (7) • (–0.4) • (5.8)
a. negative b. positive

Answers

Answer 1

Answer: Negative times a Negative equals a Positive
Positive times a Positive equals a Positive
Positive times a Negative equals a Negative
Negative times a Positive equals a Negative

1.

Negative * Negative * Negative * Negative

Positive * Positive

Positive

2

Negative * Positive * Negative * Positive * Negative

Negative * Negative * Negative

Positive * Negative

Negative

(0.01) • (–43) • (7.2) • (–86)

Positive * Negative * Positive * Negative

Negative * Negative

Positive

(–3.5) • (–16) • (7) • (–0.4) • (5.8)

Negative * Negative * Positive * Negative * Positive

Positive * Negative * Positive

Negative

Answer 2

Answer: -21.9 x -6 x -1.1 x -0.47 = +67.9338

-39 x 0.5 x -0.92 x 6.1 x -12 = -1313.208

0.01 x -43 x 7.2 x -86 = +266.25600

-3.5 x -16 x 7 x -0.4 x 5.8 = -909.44

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Can someone please explain why this is wrong?
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Can you solve 9 5/9 + 1 1/5
Which shows the expression below in simplified form? (8.1 × 105) ÷ (9 × 102)

What would be the total if 25%is 18

Answers

Answer:

Step-by-step explanation:

You would first change 25% to 0.25

Then divide 18 by 0.25 (18/0.25)

Which equals 72

Answer:

4.5 because its basically 18 divided by 4

Step-by-step explanation:

Two lines, C and D, are represented by the equations given below:Line C: y = x + 12
Line D: y = 3x + 2

Which of the following shows the solution to the system of equations and explains why?

(4, 14), because one of the lines passes through this point
(4, 14), because the point lies between the two axes
(5, 17), because both lines pass through this point
(5, 17), because the point does not lie on any axis

Answers

Bought lines need to pass same point, so:

x+12 = y = y = 3x+2
x+12=3x+2 |-2
x+10=3x |-x
10=2x |/2
5=x
x+12 = y => 5+12 = y =>y = 17

(x,y) => (5,17)

Answer:

5,17

Step-by-step explanation:

Please help! Correct answer only! I need to finish this assignment before tomorrow.In a raffle, one ticket out of 500 will win a $390 prize, three tickets will win a $230 prize, and sixteen tickets will win a $170 prize. The remaining tickets will win nothing. If you have a ticket, what is the expected payoff?

Answers

Answer: $7.60

===========================================================

Work Shown:

1/500 = 0.002 is the probability of winning $390

3/500 = 0.006 is the probability of winning $230

16/500 = 0.032 is the probability of winning $170

Multiply the probabilities with their respective winnings

0.002*390 = 0.78

0.006*230 = 1.38

0.032*170 = 5.44

Then add up those results

0.78+1.38+5.44 = 7.60

which is the expected value.

Side note: This game is not a fair game because mathematically a "fair game" is defined as such where the expected value is 0; ie, neither the player nor the dealer win and things break even.

Amanda teaches the art of quilling to 4 students. These students each teach the art of quilling to 4 other students. If this process continues for 5 generations, how many people will know the art of quilling.

Answers

1 * 4 = 4

4 * 4 (or $4^(2)$ ) = 16

16 * 4 *4 *4 *4 *4

16384 people will know the art of quilling

Which expressions are equivalent to 16x4 − 64? Check all that apply. 16x4 + 16x – 16x – 64 16x4 – 8x – 8x – 64 (4x2 + 8)(4x2 – 8) 16(x2 + 2)(x2 – 2) 4(4x4 – 8)

Answers

The given expression is $16x^(4)-64.$

It can be written as $16x^(4)+16x-16x-64.$ [ we can add or subtract the same thing]

The expression can be factored as difference of two squares

$16x^(4)-64=[4x]^(2)-(8)^(2)=(4x^(2)+8)(4x^(2)-8)$

The common factor of the two terms is 16

WE can take 16 as common factor: $16x^(4)-64=16[x^(2)-2^(2)]$

= $16(x^(2)+2)(x^(2)-2)$

Options 1 ,3,4 are the equivalent expressions.

16x^4 - 64

equivalent expressions are :
16x^4 + 16x - 16x - 64
(4x^2 + 8)(4x^2 - 8)
16(x^2 + 2)(x^2 - 2)

Geometry. Please help ASAP.In the figure, PA and PB are tangent to circle O and PD bisects ∠BPA . The figure is not drawn to scale.

A. 78
B. 33
C. 90
D. 66

Answers

Please see the pic, I'd solved your question in it.

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