Sue And Juanita Were Biking On The Track Around Their Town Park. Sue Started First. When She Had Biked 9 Laps, Juanita Had Biked 3 Laps. When Juanita Had completed 12 laps, Sue had completed 30 laps. did both rates remain steady

Answers

Answer 1
Answer:

Answer:

No. Both rates did not remain steady.

Step-by-step explanation:

  • When Sue had biked 9 laps, Juanita had biked 3 laps. This means that Juanita's rate is 3 laps for every 9 laps Sue bikes.
  • When Juanita had completed 12 laps, Sue had completed 30 laps. This implies that Sue's rate is 30 laps for every 12 laps Juanita bikes.

In conclusion, the rates did not remain steady because Sue's rate was significantly faster than Juanita's.

Answer 2
Answer: No both rates did not remain steady

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Solve the linear equation x+x+2+x+4+x+6=-28
help!!!!!!!!!!!!!!! show work

Answers

x+x+2+x+4+x+6=-28\n\n4x+12=-28\ \ |\ subtract\ 12\ to\ both\ sides\n\n4x=-28-12\n\n4x=-40\ \ | \ divide \ both \ sides\ by\ 4\n\nx=-10


x+x+2+x+4+x+6=-28\n4x=-40\nx=-10

HELP PLEASEA bucket hold holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at random.

What is the probability that the golf ball he selects is white or pink?

A.5/54

B.13/5

C.5/13

D.13/18

Answers

Answer:  The correct option is (D) (13)/(18).

Step-by-step explanation:  Given that a bucket hold holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at random.

We are to find the probability that the golf ball he selects is white or pink.

Let, 'A' denotes the event that the golf ball that Jason selects is either white or pink.

Then, n(A) = 10 + 3 = 13.

Let, 'S' denotes the sample space for the experiment.

Then, n(S) = 10 + 3 + 5 = 18.

Therefore, the probability that the probability that the golf ball Jason selects is white or pink is given by

P(A)=(n(A))/(n(S))=(13)/(18).

Thus, the required probability is (13)/(18).

Option (D) is correct.

your answer equals D

A box is 20 centimeters long and 30 centimeters high. It's volume is 3,600 cubic centimeters. What is the width of the box?

Answers

We can start by looking at what we know.

We know that volume is equal to length x width x height. Filling in this equation with the values we're given:
20cm x width x 30cm =
3600cm^3

If we divide both sides by 20cm we get:
width x 30cm = 180cm^2

Next we can divide both sides by 30cm to get our answer:

width = 6cm
First you have to add 20 and 30. That gives you 50. Then you divide 3,600 by 50 and that is 72. So 72 is the width.

Can someone please help with this problem and explain. Please answer quickly, thx :) (picture included)

Answers

exponential laws
(x^(m))^(n)=x^(mn)
x^{(m)/(n)}=\sqrt[n]{x^(m)}

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)= \sqrt[3]{m^(1)}= \sqrt[3]{m}

A restaurant offers hamburgers with one, two, or three patties. Let X represent the number of patties a randomly chosen customer orders on their hamburger. Based on previous data, here's the probability distribution of X along with summary statistics:X=# of patties 1 2 3
P(X) 0.40 0.50 0.10
Mean: μX​=1.7
Standard deviation: σX​≈0.67
The total price of each burger is set at $2 per patty. Let T represent the total price a randomly chosen customer pays for their burger. Find the mean of T

Answers

Answer:

The mean price a randomly chosen customer pays for her or his burger is US$ 3.40

Step-by-step explanation:

Let's find out the mean of T (total price a randomly chosen customer pays for their burger), this way:

Mean of T = 0.4 * $ 2 + 0.5 * $ 4 + 0.1 * $ 6

Mean of T = 0.8 + 2 + 0.6

Mean of T = US$ 3.40

The mean price a randomly chosen customer pays for her or his burger is US$ 3.40

Answer: 3.4 1.34

Step-by-step explanation: khan

Solve the system of equations.
4x + 3y + z= -6
x-3y + 2z=0
11x-2y + 3z = - 26

Answers

Answer:

y= - 271/71

x=755/71

z =4866/71

Step-by-step explanation:

For resolve a system you multiply an equation of the system or add two of the equation and replace the result in the system

                                                     Add the 1st and 2nd, and replace the 2nd

4x + 3y + z= -6         4x + 3y + z= -6          4x + 3y + z= -6

(-4) (x-3y + 2z=0) → -4x +12y -8z =0      →       +15y -7z = -6

11x-2y + 3z = - 26    11x-2y + 3z = - 26       11x-2y + 3z = - 26

                                                      Add the 2nd and 1st, and replace the 1st

4x + 3y + z= -6          4x + 3y + z= -6                    4x  + z= -6

(-1/5)( 15y -7z = -6) →  -3y -7/5z =6/5      →       -3y -7/5z =6/5

11x-2y + 3z = - 26     11x-2y + 3z = - 26           11x-2y + 3z = - 26

                                                      Add the1st and 3rd, and replace the 3erd

(-3)( 4x  + z= -6)          -12x - 3z= 18                    -12x - 3z= 18

-3y -7/5z =6/5      →  -3y -7/5z =6/5      →       -3y -7/5z =6/5

11x-2y + 3z = - 26      11x-2y + 3z = - 26           -x-2y  = - 8

                                                       Add the1st and 3rd, and replace the 1st

(1/3)(-12x - 3z= 18 )     -4x - z= 6                 -4x - z= 6

(5)(-3y -7/5z =6/5) →  -15y - 7z = 6        → -15y - 7z = 6

-x-2y  = - 8               (-4)(-x-2y  = - 8)         4x + 8y= 32

                          Add the 1st and 2nd, and replace the 2nd

(-7)(8y - z =38)        -56y +7z= 266     -56y +7z= 266

-15y - 7z = 6     →     -15y - 7z = 6  →      -71y=271 → y= - 271/71

(1/4)(4x + 8y= 12)       x+2y=3                 x+2y=3

-56y +7z= 266 → -8y + z =38 → z =4866/71

x+2y=3 → x=755/71