Answer:
fg(7) = 231
Step-by-step explanation:
The question is asking you to find fg(7), which is function of f times function of g when x = 7. To solve it, you just need to plug in the 7 where x is in both equation and then multiply these results.
f(x) = x + 4
f(7) = 7 + 4
= 11
g(x) = 3x
g(7) = 3(7)
= 21
fg(7) = 11 × 21 = 231
Answer:
1,280
The dimensions are 5 by 4
Step-by-step explanation:
You multiply 20 and 16 then, divide 0.25 then you get 1,280
Answer:1,280
Step-by-step explanation:
B. 0.946
C. 1.058
D. 1.011
(D+5)+(d+5)+(d+5)
Answer:
Final Answer: 3d+15
Step-by-step explanation:
d+5+d+5+d+5
5+5+5= 15
d+ d+ d= 3d
0.000005
0.00005
0.0005
500 seconds equates to 0.0000005 gigaseconds. This is determined by dividing 500 seconds by 1,000,000,000 seconds (the number of seconds in a gigasecond).
In the field of physics, the measure of time can be broken down into various units. The smallest unit is the second. Higher units include kiloseconds, megaseconds, and gigaseconds. One gigasecond (Gs) is equal to 109 seconds or 1,000,000,000 seconds.
To convert 500 seconds into gigaseconds, you need to divide 500 by 1,000,000,000.
So, 500 seconds = 500 / 1,000,000,000 Gs.
This calculation results in 0.0000005 Gs, which is your answer.
#SPJ11
x²-13x+42=0
Answer:
x1=7,
x2=6
Step-by-step explanation:
x²-13x+42=0
a=1, b=-13, c=42
x1,2=(-b+-sqrt(b^2-4ac)) /2a
x1,2=(-(-13)+-sqrt((-13)^2-4*1*42))/2*1
x1,2=(13+-sqrt (169-168))/2
x1,2=(13+-sqrt(1))/2
x1,2=(13+-1)/2
x1=(13+1)/2, x2=(13-1)/2
x1=14/2, x2=12/2
x1=7, x2 =6