Which is not true about neutron? (a) It is neutral particle (b) It is highly unstable in nature (c) It is present in the nucleus. (d) It contributes to the most of the atom

Answers

Answer 1

Answer: (b) It is highly unstable in nature. Neutrons are actually quite stable and are present in the nucleus.

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A good baseball pitcher can throw a baseball toward home plate at 90 mi/h with a spin of 1950 rev/min. How many revolutions does the baseball make on its way to home plate? For simplicity, assume that the 60 ft path is a straight line.

Answers

The baseball will undergo 16 revolutions on its way to home plate.

Explanation:

As the parameters which are given are speed at which the baseball is thrown, (v = 90 mi/h) and the distance between the home plate and the ball thrown is 60 ft. Also the spin is said to 1950 rev/min, it indicates that the ball will undergo 1950 revolution in every single minute. So in order to determine the number of revolutions the baseball will make in its way to home plate, we have to first determine the time taken for the baseball to reach its home plate with the given speed.

As we know that speed can be obtained by the ratio of distance with time, in the present case, we know the speed and distance, then time can be obtained by ratio of distance with speed.

At first, we have to convert the speed from mi/h to ft/min

1 mi/hr = 5280/ 60 ft/min = 88 ft/min.

Then, Time = Distance/Speed = 60/(90×80)=60/7200=8.33 × 10⁻³ min

Since the ball undergoes 1950 revolutions in 1 min, then in 8.33 × 10⁻³ min, the number of revolutions will be 1950×8.33 × 10⁻³ = 16 rev

Thus, the baseball will undergo 16 revolutions on its way to home plate.

suppose that a particle at rest with mass m decays into a photon and another particle with mass m/2 , which recoilds in a direction opposite to the photon. Using the conservation of energy and momentum find the momentum of the recoiling particle

Answers

Answer:

$p_r=(h)/(\lambda)$

Explanation:

To find the momentum of the recoiling particle you can use the momentum formula for a photon:

$p=(h)/(\lambda)$

before the decay the momentum is zero. Hence, after the decay the momentum of the photon plus the momentum of the recoiling particle must be zero:

$p_a=p_b\n\n(h)/(\lambda)-(m)/(2)v=0\n\np_r=(m)/(2)v=(h)/(\lambda)$

where pr is the momentum of the recoiling particle.

What are the two most reactive groups of elements in the periodic table?

Answers

The periodic table is a tabulated organization and representation of chemical elements that classify elements similar to repeating characteristics and order them by their increasing atomic number.

The periodic table is structured into:

rows known as periods and;
columns usually called groups.

The groups are categorized from group 1 (known as the alkali metals) to group 18 (i.e. the noble gases)

The list of the two most reactive groups are:

Alkali metals and;
The halogen family

Alkali metals i.e the group 1 metals are one of the two metals with the highest reactivity. This is owing to their greater atomic radii and lower ionization energies, among other factors. They exhibit an oxidation state of +1 and typically donate electrons in reaction with the halogen family thereby resulting in the formation of an ionic bond. They also have lower boiling and melting points than other elements and are less dense.
The halogen family which is the other group of the most reactive elements on the periodic table is distinguished by their electronegativity characteristics. i.e. their ability to attracts electrons to themselves. They are located in group 7 on the periodic table.

Thus, we can conclude that the two most reactive groups of elements in the periodic table are the alkali metals and the halogen family.

Learn more about the periodic table here:

brainly.com/question/17170685?referrer=searchResults

The Halogens and the Alkali Metals.

On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the same material. The mass is displaced by a small displacement Δy such that equal tensions T exist in the two strings, as shown in the figure. The mass is released and begins to oscillate back and forth. Assume that the displacement is small enough so that the tensions do not change appreciably. (a) Show that the restoring force on the mass can be given by F = -(2T∆y)/l (for small angles) (b) Derive an expression for the frequency of oscillation.

Answers

Answer:

ω = √(2T / (mL))

Explanation:

(a) Draw a free body diagram of the mass. There are two tension forces, one pulling down and left, the other pulling down and right.

The x-components of the tension forces cancel each other out, so the net force is in the y direction:

∑F = -2T sin θ, where θ is the angle from the horizontal.

For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m). (This is derived by solving a second order differential equation.)

In this case, k = 2T/L, so the frequency is:

ω = √((2T/L) / m)

ω = √(2T / (mL))

Which process produces the energy radiated by the star when it becomes a main sequence star?

Answers

The process that produces the energy radiated by stars is nuclear fusion in the core.
For a star on the main sequence, it's the fusion of hydrogen nuclei into helium.

An electromagnetic wave has a frequency of 2.90 × 1014 Hz. What is the wavelength of the wave? Question 17 options: 1.03 × 10–6 m 9.60 × 10–7 m 8.70 × 1022 m 2.61 × 10–21 m