Pleasee help and explain

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

ok so the y-axis is the one that goes down, so basically you want to draw the line how it is but like a how mirror does it.

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An inchworm ran into a log while on his way to the raspberry patch. The diameter of the log is 32 cm. How far did the inchworm travel while on the log?

Answers

Is the inchworm going around the log or over the log?

If it goes over the log, it simply travels the diameter, or 32 cm.

If it goes around the log, then it must travel half of the circumference, or 32*pi/2=16pi cm.

Note that this assumes that the inchworm and the raspberry patch are diametrically opposite.

Maybe I'm overthinking this one, but here's what I think it's talking about.
If I'm wrong, then I ought to at least get a few points for my talent at making
easy things difficult, and inventing obstacles to place in my own path.

-- The worm is 1 inch long.
-- The outside of the log is a cylinder. Its cross-section is a
perfect circle with a circumference of 32-cm.
-- The axis (length) of the log is perpendicular (across) the path
that leads to raspberry nirvana.
-- The ground is hard. The log contacts the ground along a line,
and doesn't sink into it at all.

-- The worm sees the log ahead of him. He continues crawling, until
he is directly under a point on the log that's 1-inch above him.
He then stands up to his full height, sticks his front legs to the log,
hoists himself up onto the bark, and starts to walk up and over it.

-- When he reaches a point on the other side of the log that's exactly 1-inch
above the ground, he hooks his sticky back feet to it, drops straight down to
the ground, and continues on his quest.

-- The question is: What's the length of the part of the log's circumference
that he traveled between the two points that are exactly 1-inch off the ground ?

I thought I was going to be able to be able to talk through this, but I can't.
I need a picture. Please see the attached picture.

Here comes the worm, heading from left to right.
He sees the log in front of him.
He doesn't bother going around it ... he knows he'll be able to get over it.

When he gets under the log, he starts standing straight up, trying to
grab onto the bark. But he can't reach it. He's too short, only 1 inch.

Finally, when he gets to point 'F', the bark is only 1" above him,
so he can hook on and haul himself up to point 'A'.

He continues on ... up, around, and over the log.

Eventually it dawns on him that the log won't last forever, and he'll
soon need to get down to the ground. As he comes down the right
side of the log, he starts looking down. It's too high. He can't reach
the ground, and he's afraid to jump.

Then he reaches point 'B'. It's exactly 1-inch above the ground, and
he leaves the log and gets down.

What was the length of the path he followed on the log ... the long way,
over the top from 'A' to 'B' ?

Here's what I did:

Draw radii from the center of the log to 'A' and 'B' .
Each of them is 16 cm long (1/2 of the diameter).

Draw the radius from the center of the log to the ground (' E ').
It's 16 cm all the way.
Point 'D' is 1 inch = 2.54 cm above the ground, so the
vertical leg of each little right triangle is (16 - 2.54) = 13.46 cm.

There are two similar right triangles, back to back, inside the log.
They are 'CAD' on the left, and 'CBD' on the right.
I want to know the size of the angles at the top of each triangle.
(One will be enough, since they're equal angles.)

For each of those angles, the side adjacent to it is 13.46 cm.
And the hypotenuse of each right triangle is a radius, so it's 16 cm.
The cosine of those angles is (adjacent/hypotenuse) = 13.46/16 = 0.84125 .
Each angle is 32.73 degrees.

Both of them put together add up to 65.45 degrees .

The full circumference of the log is (pi)(D) = 32pi cm.
The short arc between 'A' and 'B' is (65.45/360) of the full circumference.
The rest of the circumference is the distance that the worm crawled along it.

That's (1 - 65.45/360) times (32 pi) = (0.818) x (32 pi) = 82.25 cm .

Having already wasted enough time on this one in search of 5 points,
and then gone back through the whole thing to make corrections for
the customary worm crawling over the metric log, I'm not going to bother
looking for a way to check it.

That's my answer, and I'm sticking to it.

–81, 108, –144, 192, ...Which formula can be used to describe the sequence?
A.f(x) = –81(4/3)^x-1
B. f(x) = –81(-3/4)^x-1
C. f(x) = –81(-4/3)^x-1
D. f(x) = –81(3/4)^x-1

Answers

r = 108/-81 = -144/108 =192/-144 = -4/3
This is a geometric sequence with a common ratio (r) = -4/3
The nth term of a geometric sequence is given by tn = ar^(n-1) where a is the 1st term.
Therefore, the formular for the sequence is f(x) = -81(-4/3)^(x-1)
Answer: C [f(x) = -81(-4/3)^(x-1)]

Answer: C. f(x) = -81(-4/3)^(x-1)

This is just the short answer for all of you that are working on edge.nuity and don't have the time or need for a long explanation. I just took the unit test and this was correct, I hope this helped someone out there :3

The table below shows the amount of money, in hundreds of dollars, Elliot has saved after different numbers of years: Identify the function that represents Elliot's savings and the amount that Elliot will have saved in 9 years.

y = 15x, in 9 years he will have saved $13,500
y = x + 15, in 9 years he will have saved $2,400
y = 6x, in 9 years he will have saved $5,400
y = x + 90, in 9 years he will have saved $9,900

Answers

Table:
Years (x) 1 2 3 4 5 6
Money (y) (hundreds of dollars) 15 30 45 60 75 90

y = 15(x)
y = 15(9)
y = 135 hundreds of dollars

y = 15x, in 9 years he will have saved $13,500

Answer:it’s a, 13,500. I took the test

Step-by-step explanation:

Tai went to a shopping mall. He spent $25.75 on a shirt, $15.49 on a hat, and $9.95 on a poster, before tax. Taxwas 8.25% on all purchases. What was the total cost of Tai's purchases, including tax?

Answers

Answer: 39.98$

Hope it helped it took me like 10 minutes <3

Physics students drop a ball from the top of a 100 foot high building and model its height above the ground as a function of time with the equation   2 ht   . The height, h, is measures in feet and time, t, is 100 16 t measured in seconds. Be careful with all calculations in this problems and remember to do the exponent (squaring) first.

Answers

Complete question :

Physics students drop a ball from the top of a 100 foot high building and model its height as a function time with the equation h(t) = 100 - 16t^2.The height, h, is measured in feet and time, t, is measured is seconds.

Find the value of h(0). Include proper units. What does this output represent?

Answer:

Kindly check explanation

Step-by-step explanation:

The model given :

Height, h as a function of time :

h(t) = 100 - 16t^2

To find h(0): substitute 0 for t in the model defined ;

h(0) = 100 - 16(0)²

h(0) = 100 - 0

h(0) = 100

The output gives the height at which the ball was before it was dropped, it depicts the height when the travel time of the ball is 0

The front and back covers of a textbook are each 0.3 cm thick. Between the covers are 200 sheets of paper, each 0.008 cm thick. How high is a stack of 10 books

Answers

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. The height of the 10 stacks of books is 22cm.

What is multiplication?

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. For example, 3 × 4 means 3 is added to itself 4 times, and vice versa for the other number.

Given that the front and back covers of a textbook are each 0.3 cm thick. Also, there are 200 sheets of paper between the cover and the thickness of each sheet is 200 sheets. Therefore, the thickness of the book is,

The thickness of a single book

= (Number of covers × Thickness of cover) + (Number of sheets × Thickness of sheets)

= (2 × 0.3cm) + (200 × 0.008cm)

= 2.2 cm

Now, the thickness of 10 books will be,

The thickness of 10 books = 10 × the Thickness of a single book

= 10 × 2.2 cm

= 22 cm

Hence, the height of the 10 stacks of books is 22cm.

Learn more about Multiplication here:

brainly.com/question/14059007

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