Inverse operations 15x+8=6

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Answer 1

Answer:

Answer:

1 step. multiplayer with 8 and find their sum the difference between the temperature recorded on llllll

Related Questions

A bakery has 4 trays with 16 muffins on each tray. The bakery has 3 trays of cupcakes with 24cupcakes on each tray. If 15cupcakes are sold, how many muffins and cupcakes are left?
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Simplify -2 x (4) -3 x (-5)
A spring has an original length L inches. When a weight of x pounds is suspended from the spring, its new length y is given by the formula y = L + x k , where k is a constant, measured in pounds per inch. Solve the formula for x. Show the steps in your work. The value of k for a certain spring is 2.5. The length of the spring is found to be double its original length when a 10 pound weight is suspended from it. Write the equation for the original length of the spring and solve it. Show the steps in your work.

Please help!The guidelines for a healthy adult are to maintain a Body Mass Index (BMI) between 19.5 and 24.9. A formula that relates the height of an adult to his or her weight and BMI is shown in the picture below, where h=height in inches, w=weight in pounds, and M=BMI.

1.) Find the formula that will directly calculate BMI given a person's height and weight.

2.) Chris weighs 211 pounds and has a BMI of 28.5. How many whole pounds must he gain or lose to get into the healthy BMI range?

Thank you!!

Answers

1. $h=40\sqrt{(.45w)/(M)}\Rightarrow(h^2)/(1600)=\frac{.45w}M\Rightarrow M=(720w)/(h^2)$

2. his BMI has to be reduced by 28.5-24.9=3.6

We must thus solve $(720w)/(h^2)=3.6$ thus $(720w)/(h^2)=3.6h^2/720=.005h^2$ . We can know his height using the first formula : $h=40\sqrt{(.45w)/(M)}=40\sqrt{(.45*211)/(28.5)}\approx73.01$

Hence he must lose $(73.01)^2*.005\approx26.6$ -> 27 pounds.

We check our result : $720*(211-27)/(73.01^2)\approx24.85<24.9$

To answer the first problem you are going to need to solve the equation for M (BMI). In order to do this you need to rearrange the variables h and w to one side of the equation, and M by itself on the other side. After doing this your equation should look like:
M = (0.45*w) / ((h / 40)^2)

For part 2 we must first solve for Chris' height so that we can find his healthy range. You should use the original equation for this. You should get 73.0105 inches as an answer. Now we must solve for his weight using 24.9 as the upper limit of the healthy BMI range as well as his height. You need a new formula solving for w. I am not going to put this formula here but I will just solve for W.
His healthy weight in pounds turns out to be 184.348 pounds. In order to get into this range, he must lose 211 - 184.348 = 26.6524 pounds. Since it asks how many whole pounds he must lose you should put 27 pounds as your answer.
Hope this helped!

The average cost of tuition and room and board at a small private liberal arts college is reported to be $8,500 per term. A financial administrator believes that the average cost is higher. A study conducted using 350 small liberal arts colleges showed that the average cost per term is $8,745. The population standard deviation is $1,200. Let α

Answers

Answer:

D. +3.82

Step-by-step explanation:

The computation of the test static for this test is shown below:

Data provided in the question

$\bar x$ = $8,745

$\mu$ = $8,500

$\sigma$ = $1,200 and n = 350

Now based on the above information, the test static for this test is

$z = (\bar x - \mu)/((\sigma)/(√(n) ) )$

$z = (\$8,745 - \$8,500)/((\$1,200)/(√(350) ) ) \n$

= 3.82

= +3.82

Hence, the test static for this test is +3.82

We simply applied the above formula so that the correct value could come

And, the same is to be considered

The vertex of the parabola y = x2 + 8x + 10 lies in Quadrant

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$y = x^2 + 8x + 10\n\nThe\ vertex=(p;\ q)\ \ \ and\ \ \ p=- (b)/(2a) ;\ \ \ q=- (\Delta)/(4a) ;\ \ \ \Delta=b^2-4ac\n\n\Delta=8^2-4\cdot1\cdot10=64-40=24\n\np=- (8)/(2\cdot1) =-4\n\nq=- (24)/(4\cdot1) =-6\n\nthe\ vertex=(-4;-6)$

$y = x^2 + 8x + 10 \n \nthe \ standard \ form \ y = ax^2 + bx + c \n\nof \ a \ function \ into \ vertex \ form \ y = a(x - h)^2 + k ,\n \n we \ have \ to \ write \ the \ equation \ in \ the \ complete \ square \ form \n\n\ and \ vertex(h, k) \ is \ given \ by:$

$h = (-b)/(2a) , \ \ k = c -(b^2)/(4a ) \n \ny = a(x - h)^2+k$

opens up for a > 0

$a=1 , \ \ b=8, \ \ c=10 \n \nh= (-8)/(2)=-4$

$k= 10-(8^2)/(4)=10-(64)/(4)=10-16=-6 \n \ny=(x-(-4))^2+(-6)\n \ny=(x+4)^2-6$

(a+b) to the power of two a= -3 and b= 6.

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Answer:

Step-by-step explanation:

-3+6 is 3

3*3 is 9

Write an equation
Eight times the sum of m and 7 is 21

Answers

Answer:

the equation would be 8(m+7)=21

8 ( m + 7 ) = 2 1
your welcome ! <3

Caleb draws 14 dogs on each of 4 posters.He draws 18 cats on each of 6 other posters. If he draws 5 more dogs on each poster with dogs, how many dogs ad cats does he draws?

Answers

Caleb draws 14 dogs on each of 4 posters.
Then,
Number of dogs drawn by caleb in the first instance = (14 * 4) dogs
      = 56 dogs
Celeb drew 18 cats on each of 6 other posters.
Then
Number of cats drawn by Caleb in the first instance = (18 * 6) cats
   = 108 cats
Again Caleb draws 5 more dogs on each poster with dogs.
Then,
The number of Dogs drwn in the second instance = (5 * 4) dogs
   = 20 dogs
So, the total number of dogs drawn by Caleb = ( 56 + 20) dogs
   = 76 dogs
Then the total number of cats and dogs drawn by Caleb = 108 + 76
   = 184

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