MATHEMATICS HIGH SCHOOL

Please help due tomorrow

Answers

Answer 1

Answer:

Answer:

we can't even see it

Step-by-step explanation:

it's very blurry

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Which statement justifies that 3x^2 − x − 5 multiplied by 2x^2 − x − 3 obeys the closure property of multiplication?The result 6x^4 + x^2 + 15 has a degree of 4. The result 6x^4 + x^2 + 15 is a trinomial. The result 6x^4 − 5x^3 − 18x^2 + 8x + 15 is a polynomial. The result 6x^4 − 5x^3 − 18x ^2 + 8x + 15 has a degree of 4.

What is the area of a square with sides of length 6?

Answers

Answer:

Step-by-step explanation:

6 squared

Answer:

A= 36

Step-by-step explanation:

Faye’s bank charges her a $2.25 service fee every time she uses an out-of-network ATM. If Faye uses an out-of-network ATM twice a week, how much money does she pay in service fees every year?

Answers

$2.25+$2.25=$4.50 Twice a week
52 weeks in a year
$4.50x52 weeks = $234

Answer: D. $234.00

Step-by-step explanation:

Just took a test and answered it correct.

What is 23 squared A. 1,058 B.129 C. 46 D. 529

Answers

The value of 23 squared is 529

What is square of a number?

A square number or perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself.

For example, the 3² is 3 × 3 i.e the product of the 3 by itself , which is 9

Similarly, the square of 23 is 23² which is the same as the 23 × 23

= 529

Therefore the square of 23 is 529. this means that 23² = 529 and the square root of 529 is 23.

learn more about square of numbers from

brainly.com/question/27307830

#SPJ6

23 squared is 529 because 23 x 23 is 529, so the answer is D.

Find all real number x such that
6x-21≥3 or 14x+11≤-7

Answers

$6x-21 \geq 3\n \n 6x \geq 3+21\n \n 6x \geq 24\n \n x \geq (24)/(6)\n \n \boxed{x \geq 4}$

$14x+11 \leq -7\n \n 14x \leq -7-11\n \n 14x \leq -18\n \n x \leq (19)/(14)\n \n x \leq (9)/(7)$

7x^2-31x+20 I Know The Answer, I Just Don't Know The Steps To Solving This Equation.

Answers

$7x^2-31x+20=0$
First, remove the coefficient by division
So
$(7x^2)/(7)-(31x)/(7)+(20)/(7)=0$
Then, cancel out $(20)/(7)$
So,
$x^2-(31x)/(7)+(20)/(7)-(20)/(7)=-(20)/(7)$
Then take half of the coefficient, then square it.
$(-(31)/(7))/(2)=(37)/(14)$
$(-(37)/(14))^2=(961)/(196)$
So, The equation already looks like this:
$x^2-(31)/(7)+(961)/(196)=-(20)/(7)+(961)/(196)$
So,
$x^2-(31)/(7)+(961)/(196)=(401)/(196)$
Then factor the left side of the equation:
$(x-(31)/(14))^2=(401)/(196)$
Then square both sides:
$x-(31)/(14)=\sqrt{(401)/(196)}$

$7x^2-31x+20=0\n \n \Delta=(-31)^2-4.7.20=961-560=401\n \n x=\frac{31 \pmsqrt{401}}{2*7}=(31 \pm√(401))/(14)$

Simplify. x+5/x^2+6x+5 1/x+1; where x ≠ -1
1/x+1; where x ≠ -1, -5
1/x-5; where x ≠ 5
x-5

Answers

Answer:

The correct option is 2.

Step-by-step explanation:

The given rational expression is

$(x+5)/(x^2+6x+5)$

Factorize the denominator.

The middle term can be written as 5x+x.

$(x+5)/(x^2+5x+x+5)$

$(x+5)/(x(x+5)+1(x+5))$

$(x+5)/((x+5)(x+1))$

Cancel out the common factors.

$(1)/(x+1)$

The simplified form of the given expression is $(1)/(x+1)$ . The factors of the denominator are (x+5) and (x+1), it means at x=-5 and x=-1, the value of denominator is zero.

The given expression is not defined for x=-1 and x=-5.

Therefore the correct option is 2.

x+5/x^2+6x+5
x+5/(x+5)(x+1)
1/x+1

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