If LA and LB are complementary,What is the sum of their measure?

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Answer 1

Answer:

90 degrees

Step-by-step explanation:

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Points B, D, and F are mid points of the sides of triangle ACE. CE=38 and DF= 16. Find AC. The diagram is not drawn to scale.

Answers

I hope this helps you

find the volume of a can of chicken broth that had a diameter of 7.5cm and a height of 11cm. round 5o the neatest tenth

Answers

cans are normally cylinders
Vcylinder=hpir^2

h=11

d/2=r
7.5/2=3.75=r

V=11pi3.75^2
V=11pi14.0625
V=154.6875pi
aprox pi=3.141592 and multiply
V=485.96
round tenth
486.0 cm^3

Simplify the expression
16+(-3)-3/7j-5/7j+4

Answers

the simplified version is
119j-8/7j

Jenny decides to save her babysitting money for her college education instead of using it to buy a new outfit. Jenny's choice is an example of which of the following economic principles? Select the best answer from the choices provided. a cost-benefit analysis the law of supply the law of demand a trade-off NextReset]

Answers

The correct answer is trade off.

A motorcycle and a car leave an intersection at the same time. the motorcycle heads north at an average speed of 20 miles per hour, while the car heads east at an average speed of 48 miles per hour. find an expression for their distance apart in miles at the end of t hours.

Answers

An expression relating the distance between the car and motorcycle after t is 52t

Speed of motorcycle = 20 mph

Speed of car = 48 mph

Distance apart after, t hours :

Recall :

Distance traveled = Speed × time

Hence,

Distance traveled by car after t hours

Distance of car = 48t

Distance traveled by Motorcycle after t hours

Distance of motorcycle = 20t

Since, the direction followed by the car and motorcycle forms a right angle, the distance apart after t hours can obtained using Pythagoras :

Recall from Pythagoras :

a² = b² + c²

Where, a = hypotenus

b and c = opposite and adjacent

Therefore, distance apart :

d² = (48t)² + (20t)²

d² = 2304t² + 400t²

d² = 2704t²

Take the square root of both sides :

d = √2704t²

d = 52t

Therefore, the distance between the car and motorcycle after t hours is : 52t

Learn more : brainly.com/question/8283882

First, determine the distance of the motorcycle and the car from the start point. The distance could be determined using
$\boxed{d=v * t}$
d stands for distance, v stands for speed, t stands for time

The car
d = 48 × t
d = 48t

The motorcycle
d = 20 × t
d = 20t

At the end of t hours, the car is 48t miles (east) from the start point and the motorcycle is 20t miles (north) from the start point.

Second, determine the distance between 48t miles at east and 20t miles at north using pythagoras
distance = $\sqrt{(48t)^(2)+(20t)^(2)}$
distance = $\sqrt{2304t^(2)+400t^(2)}$
distance = $\sqrt{2704t^(2)}$
distance = 52t

The expression for their distance apart at the end of t hours is 52t

Z+w−3=k
6z−10w=8

Answers

Answer:

if your looking for z it is 5/8k+2.375

Step-by-step explanation:

Answer:

Step-by-step explanation:

Please, include the instructions.

I'm assuming you want to solve this system of linear equations for z and w, assuming that k is an unknown constant.

Use the method of elimination by addition and subtraction. To eiiminate w, multiply all four terms of the first equation by 10, obtaining:

10 z + 10w - 30 = 10k

6z - 10 w = 80

Then 16z - 30 - 80 = 10k, or

16z -110 = 10k, Simplifying this, we get:

10(k + 11)

z = ---------------

Substituting this expression for z into the first equation, we get:

(10/16)(k + 11) + w - 3 = k. We must solve this for w:

-(10/16)(k + 11) + w - 3 = k), or

-(10/16)(k + 11) - w + 3 = -k

Then -(10/16)(k + 11) + 3 + k = w

and so the solution, in terms of the unknown constant k, is

10(k + 11)

( --------------, -(10/16)(k + 11) + 3 + k )

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