digits from 0 to 9. Digits cannot be
repeated. Find the probability that
randomly generated card has the
exact number 94213.
Answer:
Step-by-step explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
A can be any of 10 digits
B can any of the remaining 9 digits
C can be any of the remaining 8 digits
D can be any of the remaining 7 digits
E can be any of the remaining 6 digits
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of
Hence, the probability of having 94213 is
9.55 as a mixed number would be 9 11/20.
9.55 = 9 55/100 = 9 11/20
Hope this helps !
True
False
Answer: We are given Quadrilateral LMNO is reflected over a line.
Also given Quadrilateral LMNO is congruent Quadrilateral CDAB, that is
LMNO ≅ CDAB.
Note: Reflection over a line represents mirror images of the figures.
From the given image we can see
LM is congruent to CD.
ON is congruent to BA.
LO is congruent to BC.
MN is congruent to AD.
Therefore, DC segment corresponds to ML.
Hope i helped you out!