PHYSICS HIGH SCHOOL

Which of the following is not a unit of pressure? a. atmosphere b. psi c. N/m^2 d. mm of mercury e. pascal f. They are all units of pressure.

Answers

Answer 1

Answer:

Answer:

(A) Atmosphere.

Explanation:

The atmosphere is a thing, not a unit of measurement. (this is the simplified version)

Pls mark brianlist

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Friction is a force, too. How can friction help you in your daily life? How can it hurt you?ASAP PLEASEEEEE

Answers

Answer:

It can hurt you if you get a carpet burn if you rub against carpet really fast and hard. It can help by keeping your shoes from slipping around all the time when you walk/run. Same with bike tires.

Explanation:

The waste products of a nuclear fission powerplant can best be described asa. Small in quantity and not very dangerous.
b. Large in quantity and not very dangerous.
c. Large in quantity and very dangerously radioactive. Eliminate
d. Small in quantity and very dangerously radioactive.

Answers

The answer is D. small in quantity and very dangerously radioactive.

a.

-> the products are stable atoms with a much lower atomic number. For example, Uranium 238 commonly breaks down into strontium and xenon, both of which are stable and non-radioactive.

They are also low in quantity because of the precision involved in breaking down a large atom via neutron capture means that few fission reactions take place.

Hope I helped :)

Source: I studied nuclear physics in year 11

A ball rolls from point A to point B. The total energy of the ball at point A isn’t the same as the sum of its potential energy and kinetic energy at point B. Which statement best explains this situation?The rolling ball doesn’t follow the law of conservation of energy.

Some of the ball’s energy is transformed to thermal energy.

The rolling ball loses some of its energy because of gravity.

The ball absorbs some of its own potential energy.

Answers

The rolling ball loses some of its energy because of gravity. Gravity and friction are two factors that slows the acceleration of the ball causing the ball to slow down at point B. If the situation is a free fall, then gravity is a factor, but if it is in a horizontal displacement,then there is friction that counterflows against the applied force.

Some of the ball’s energy is transformed to thermal energy.

Conservation of mechanical energy

The principle of conservation of energy states that sum of potential energy and kinetic energy is constant.

M.A = P.E + K.E

where;

P.E is the potential energy
K.E is the kinetic energy

The mechanical energy is always conserved, although it may be converted from one form to another.

The rolling ball follows the law of conservation of energy, the lost energy may be transformed to thermal energy.

Learn more about conservation of energy: brainly.com/question/166559

The earth has a downward-directed electric field near its surface of about 150 N>C. If a raindrop with a diameter of 0.020 mm is suspended, motionless, in this field, how many excess electrons must it have on its surface?

Answers

Answer:

$Q = 2.74 * 10^(-13) C$

Explanation:

A rain drop has diameter given as

$d = 0.020 mm$

so the radius of the rain drop will be

$R = 0.010 mm$

now the volume of the rain drop is given as

$V = (4)/(3)\pi R^3$

$V = (4)/(3)\pi(0.010* 10^(-3))^3$

$V = 4.19 * 10^(-15) m^3$

now weight of the rain drop is given as

$W = \rho V g$

$W = (1000)(4.19 * 10^(-15))(9.81)$

$W = 4.11 * 10^(-11) N$

now this weight of the rain drop is counterbalanced by force due to electric field

so we have

$QE = W$

$Q = (W)/(E)$

$Q = (4.11 * 10^(-11))/(150)$

$Q = 2.74 * 10^(-13) C$

Final answer:

To determine the number of excess electrons on the surface of the raindrop, we can use the formula: mdrop = qeE. The electric field near the Earth's surface is given as 150 N/C. The mass of the raindrop can be calculated using its diameter.

Explanation:

To determine the number of excess electrons on the surface of the raindrop, we can use the formula:
mdrop = qeE

The electric field near the Earth's surface is given as 150 N/C. The mass of the raindrop can be calculated using its diameter. Once we have the mass, we can solve for the charge (qe) to find the number of excess electrons on its surface.

Let me calculate that for you.

Learn more about Excess electrons on a raindrop's surface here:

brainly.com/question/13274362

#SPJ12

2. The speed of truck is 39 m/s. How long does it take for the truck to travel 9,000 m?

Answers

Answer:

$\boxed {\tt 230.769231 \ seconds}$

Explanation:

Time can be found by dividing the distance by the speed.

$t=(d)/(s)$

The distance is 9,000 meters and the speed is 39 meters per second.

$d= 9,000 \ s\ns=39 \ m/s$

Substitute the values into the formula.

$t=(9,000 \ m)/(39 \ m/s)$

Divide. Note that the meters, or "m" will cancel out.

$t=(9,000)/(39 \ s)$

$t=230.769231 \ s$

It takes 230.769231 seconds for the truck to travel 9,000 meters at 39 meters per second.

Phase changes are not associated with a change in

Answers

Phase changes are not associated with a change in frequency,
wavelength, amplitude, color, volume, mass, national origin,
ethnicity, loudness, weight, opacity, or unit cost.

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