A student has a source of radiation that emits one of a, ß or y radiation. She places thesource opposite a Geiger-Müller tube and detector and records the count rate. She then
places a sheet of paper between the source and the detector and records the count rate,
and then repeats this with a sheet of aluminium instead of paper. Describe how her
results will allow her to work out which type of radiation is emitted by the source.

Please help :)

Answers

Answer 1

Answer:

Answer:

Beta radiation

Explanation:

Radiation differs in its ability to penetrate a material (or air) - alpha particle has the least penetrating power and thus is stopped by the paper. Both beta and gamma particles have higher penetrating power than alpha - they passed through. However, radiation was stopped by a sheet of aluminium, which indicates a beta particles, since gamma radiation particles (photons) can easily pass through aluminium and some solid lead block is required to stop it.

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Which factors are used the calculate the kinetic energy of an object? Check all that apply. gravity velocity volume mass height

Answers

The factors that are included in the calculation of the kinetic energy of an object would be the velocity and its mass. The kinetic energy's formula is half of the product of the mass and the velocity that is squared. The volume, height, and gravity are not included.

Kinetic energy = (1/2) (the object's mass) (its speed or velocity)² .

No other quantities are involved.

Objects on the moon's surface have an acceleration due to gravity one-sixth that on the earth's. What would the 40 kg boy weigh on the moon? (Round answer to nearest tenth.)

Answers

acceleration is the same as the gravitational force. On earth that is 9.81 m/s^2. F=ma so if the acceleration is 1/6, then so if the force (weight). 40/6 N is your answer.

If you had a planet to choose from to live in what would it be?

Answers

I personally would live on Mars cuz that is red cuz

I would personally like to live on mars because it is like our temperature, but a little bit colder.

A 111 ‑turn circular coil of radius 2.11 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicular to the plane of the coil. The coil is connected to a 14.1 Ω resistor to create a closed circuit. During a time interval of 0.125 s, the magnetic field strength decreases uniformly from 0.669 T to zero. Find the energy, in millijoules, that is dissipated in the resistor during this time interval.

Answers

Answer:

0.0061 J

Explanation:

Parameters given:

Number of turns, N = 111

Radius of turn, r = 2.11 cm = 0.0211 m

Resistance, R = 14.1 ohms

Time taken, t = 0.125 s

Initial magnetic field, Bin = 0.669 T

Final magnetic field, Bfin = 0 T

The energy dissipated in the resistor is given as:

E = P * t

Where P = Power dissipated in the resistor

Power, P, is given as:

P = V² / R

Hence, energy will be:

E = (V² * t) / R

To find the induced voltage (EMF), V:

EMF = [-(Bfin - Bin) * N * A] / t

A is Area of coil

EMF = [-(0 - 0.669) * 111 * pi * 0.0211²] / 0.125

EMF = 0.83 V

Hence, the energy dissipated will be:

E = (0.83² * 0.125) / 14.1

E = 0.0061 J

A system uses 2,380 J of energy to do work as 12,900 J of heat are added to the system. What is the change in internal energy of the system?

Answers

The internal energy of the system is characterized by the equation U = Q + W where U is the internal energy, Q is the heat and W is work. You are given 2,380 J of energy to do work as 12,900 J of heat so add up. The internal energy is 15,280J.

Explanation:

The relation between change in internal energy, work and heat is as follows.

$Q = \Delta U + W$

where, Q = heat absorbed or released by the system

$\Delta U$ = change in internal energy

W = work done by or on the system

It is given that system uses 2,380 J of energy to do work. This means that work is done by the system therefore, the value of work done by the system is negative. Heat added to the system is 12,900 J.

Therefore, calculate change in internal energy as follows.

$\Delta U = Q - W$

= 12,900 J - (-2,380 J)

= (12,900 + 2,380) J

= 15,280 J

Thus, we can conclude that the change in internal energy of the system is 15,280 J.

A speedy rabbit is hopping to the right with a velocity of 4.0 \,\dfrac{\text m}{\text s}4.0 s m 4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when it sees a carrot in the distance. The rabbit speeds up to its maximum velocity of 13 \,\dfrac{\text m}{\text s}13 s m 13, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with a constant acceleration of 2.0 \,\dfrac{\text m}{\text s^2}2.0 s 2 m 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction rightward.

Answers

Answer: 38.25 m

Explanation:

In this situation we need to find the distance $d$ between the rabbit and the carrot, and we can use the following equation, since the rabbit's acceleration is constant: