MATHEMATICS HIGH SCHOOL

A chef bought 58 kilograms of almonds and 0.2 kilograms of pecans. How many kilograms of nuts did the chef buy in all? Option 1: 58.2 kilograms. Option 2: 58.2 grams. Option 3: 58.02 kilograms. Option 4: 0.58 kilograms.

Answers

Answer 1

Answer:

Answer:

Option 1

Step-by-step explanation:

58.0kg +0.2kg = 58.2kg

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The plot has an area of 78,125 square meters and is 125 meters wide. What is the length of the plot?

Answers

625 meters long is the correct answer

Area formula: A = l * w or Area = length * width
Area: 78,125
Width: 125
Length: ?
78,125 = 125l
78,125/125 = 125l/125
625 = l

PLEASE HELP Describe the graph of the function f(x) = x3 − 18x2 + 107x − 210. Include the y-intercept, x-intercepts, and the shape of the graph.

Answers

f(x) = x³ - 18x² + 107x - 210

X - Intercept: f(x) = x³ - 18x² + 107x - 210
   0 = x³ - 18x³ + 107x - 210
       0 = x³ - 7x² - 11x² + 77x + 30x - 210
       0 = x²(x) - x²(7) - 11x(x) + 11x(7) + 30(x) - 30(7)
         0 = x²(x - 7) - 11x(x - 7) + 30(x - 7)
   0 = (x² - 11x + 30)(x - 7)
   0 = (x² - 6x - 5x + 30)(x - 7)
   0 = (x(x) - x(6) - 5(x) + 5(6))(x - 7)
   0 = (x(x - 6) - 5(x - 6))(x - 7)
   0 = (x - 5)(x - 6)(x - 7)
   0 = x - 5   or 0 = x - 6 or 0 = x - 7
+ 5 + 5 + 6 + 6 + 7 + 7
   5 = x or    6 = x or    7 = x
Solution Set: {5, 6, 7}

Y - Intercept: f(x) = x³ - 18x² + 107x - 210
      f(x) = (0)³ - 18(0)² + 108(0) - 210)
      f(x) = 0 - 18(0) + 0 - 210
    f(x) = 0 - 0 - 210
    f(x) = 0 - 210
    f(x) = -210

Shape of the Graph: Odd Degree Polynomials With a Positive Leading Coefficient

Answer:

X - Intercept: f(x) = x³ - 18x² + 107x - 210

0 = x³ - 18x³ + 107x - 210

0 = x³ - 7x² - 11x² + 77x + 30x - 210

0 = x²(x) - x²(7) - 11x(x) + 11x(7) + 30(x) - 30(7)

0 = x²(x - 7) - 11x(x - 7) + 30(x - 7)

0 = (x² - 11x + 30)(x - 7)

0 = (x² - 6x - 5x + 30)(x - 7)

0 = (x(x) - x(6) - 5(x) + 5(6))(x - 7)

0 = (x(x - 6) - 5(x - 6))(x - 7)

0 = (x - 5)(x - 6)(x - 7)

0 = x - 5 or 0 = x - 6 or 0 = x - 7

+ 5 + 5 + 6 + 6 + 7 + 7

5 = x or 6 = x or 7 = x

Solution Set: {5, 6, 7}

Y - Intercept: f(x) = x³ - 18x² + 107x - 210

f(x) = (0)³ - 18(0)² + 108(0) - 210)

f(x) = 0 - 18(0) + 0 - 210

f(x) = 0 - 0 - 210

f(x) = 0 - 210

f(x) = -210

4(4x + 3) + 6(2 - x) - 3(2x - 1) = 19

Answers

your answer is -2.
4(4x+3)+6(2-x)-3(2x-1)=19
4*4x=16x
4*3=12
6*2=12 and 6*x=6x
-3*2x=-6 and -3*-1=-3. then collect
like term. is long just cant type it but that is your answer

4(4x + 3) + 6(2 - x) - 3(2x - 1) = 19 the answer would be -2

Simplify $(1-3i)(1-i)(1+i)(1+3i)$

Answers

$(1-3i)(1-i)(1+i)(1+3i)=\n(1^2-(3i)^2)(1^2-i^2)=\n(1+9)(1+1)=\n10\cdot2=20$

Answer:

$\huge\boxed{(1-3i)(1-i)(1+i)(1+3i)=20}$

Step-by-step explanation:

$(1-3i)(1-i)(1+i)(1+3i)\n\n\text{use the commutative property}\n\n=(1-3i)(1+3i)(1-i)(1+i)\n\n\text{use the associative property}\n\n=\bigg[(1-3i)(1+3i)\bigg]\bigg[(1-i)(1+i)\bigg]\n\n\text{use}\ (a-b)(a+b)=a^2-b^2\n\n=\bigg[1^2-(3i)^2\bigg]\bigg[1^2-i^2\bigg]\n\n=\bigg(1-9i^2\bigg)\bigg(1-i^2\bigg)\n\n\text{use}\ i=√(-1)\to i^2=-1\n\n=\bigg(1-9(-1)\bigg)\bigg(1-(-1)\bigg)\n\n=\bigg(1+9\bigg)\bigg(1+1\bigg)\n\n=(10)(2)\n\n=20$

Kendall is working on a math worksheet with 40 problems. He has completed 20 problems in 15 minutes. If he continues at the same pace, how long should it take him to finish the worksheet?20 minutes
25 minutes
30 minutes
35 minutes