MATHEMATICS HIGH SCHOOL

24,25,26 is a pythagorean triplet. True or fals​

Answers

Answer 1
Answer:

Step-by-step explanation:

for this the Pythagoras equation must be true :

c² = a² + b²

c is the Hypotenuse the dude opposite of the right angle in a right-angled triangle.

as such it had to be the longest side.

so, c = 26

and we get

26² = 24² + 25²

676 = 576 + 625 = 1201

wrong, 1201 is not equal to 676, so, 24, 25, 26 are NOT a pythagorean triplet.

theinitialstatementisfalse.

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The pair of points( 6 ,y) and (10, -1) lie on a line with slope 1/4. What is the value of y?

Answers

We know that general formula for the line is y=ax+b, we know that a=1/2. To get b we can subsittute x=10 and y=-1 (from the second point)
-1=1/2*10+b
-1=5+b     /-5
-6=b
We know that our line is y=1/2x-6
Now we can substitute x=6 (from first point) and find value of y
y=1/2*6-6
y=3-6
y=-3 - its the answer

Hi can someone help me ty happy holiday days

Answers

Answer:

128 ,  512,  2048

Step-by-step explanation:

Which are vertical angels?

Answers

Answer:

Those angles are in opposite either in vertical or horizontal. They are opposite angles

what are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution

Answers

Consider the given quadratic equation 50-x^2=0

x^2-50=0

Comparing the given quadratic equation to the general equation ax^2+bx+c=0, we get a= 1, b=0 and c= -50

So, the solution to the quadratic equation is given by:

x = (-b \pm √(b^2-4ac))/(2a)

x = (-0 \pm √(0^2-4(1)(-50)))/(2)

x = (\pm √(200))/(2)

x = \pm \sqrt2 (5)

x = \pm 5\sqrt2

So, the solutions to the given quadratic equation are x = \pm 5\sqrt2.

Answer:

c

Step-by-step explanation:

.......................

What is 2/5 of 20???

Answers

(2)/(5)\ of\ 20\Rightarrow(2)/(5)*20=(2)/(5)*(20)/(1)=(40)/(5)=8
2/5 of 20 = 20/5 * 2 = 4 * 2 = 8

How many roots do the following equations have? -12x^2 - 25x+5 +x^3=0

Answers

Answer:

There are 3 roots of the given equation.

Step-by-step explanation:

Given the equation      

-12x^2-25x+5+x^3=0

we have to tell the number of roots of the given equation.

As the number of roots for an equation is equal to degree.

The degree of a polynomial is the highest power of its monomials  with non-zero coefficients.

Hence, number of roots is the highest power in the equation.

Now, the equation is -12x^2-25x+5+x^3=0

The highest power i.e degree of equation is 3.

hence, there are 3 roots of the given equation.
-12x^2 - 25x + 5 + x^(3) = 0
x^(3) - 12x^(2) - 25x + 5 = 0
x = \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) + \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} + \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) - \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} - (b)/(3a)
x = \sqrt[3]{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) + \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3)}} + \sqrt[3]{((-(-12)^(3))/(27(1)^(3))}} + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) - \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3) - (-12)/(3(1))}}
x = \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) + \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} + \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) - \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} - (-12)/(3)
x = \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) + \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} + \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) - \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} - 4
x = \sqrt[3]{(64 + 50 - 2(1)/(2)) + \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} + sqrt[3]{(64 + 50 - 2(1)/(2)) - \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} - 4
x = \sqrt[3]{(114 - 2(1)/(2)) + \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} + \sqrt[3]{(114 - 2(1)/(2)) - \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} - 4
x = \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - 4
x = \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} + \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} - 4
x = \sqrt[3]{112(1)/(2) + √(-1751.787)} + \sqrt[3]{112(1)/(2) - √(-1751.787)} - 4
x = \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i} - 4
x = -4 + \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i}
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