After subtracting the initial 5-minute cost from the total balance and dividing by the cost of additional minutes, you would have about 24 minutes remaining on your long-distance calling card when rounding to the nearest whole number.
To solve how many minutes you have remaining on your long-distance calling card, you'll first need to subtract the cost of the first 5-minute period from your total balance, which gives you $12.00 - $4.25 = $7.75.
Next, you would divide this amount by the cost of each additional minute which is $0.40. This calculation ( $7.75 / $0.40 ) results in a total of approximately 19.375 minutes.
Therefore, since you already have 5 minutes from the initial payment, you would add these two values together (5 + 19 = 24 minutes). But, according to the task you need to round your answer to the nearest whole number. As such, you can say you have approximately 24 minutes left on your card.
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To determine the number of minutes remaining on the calling card, subtract the cost of the first 5 minutes from the remaining balance and divide by the additional cost per minute. You have approximately 19 minutes remaining on the calling card.
To determine the number of minutes remaining on the calling card, we need to subtract the cost of the first 5 minutes from the remaining balance and then divide the result by the additional cost per minute.
Therefore, you have approximately 19 minutes remaining on the calling card.
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Answer:
= h
Step-by-step explanation:
Lets try and get everything we can away from h.
V =
Divide from both sides of the equation.
Now we end up with:
= h
Answer: The answer is C. c = 60d - 0.05
Step-by-step explanation:
Answer:
Step-by-step explanation:
AB + BC = AC
4x + 10 + 2x + 3 = 9x - 15
6x + 13 = 9x - 15
6x + 13 + 15 = 9x
6x + 28 = 9x
3x = 28
x = 9 1/3 = 28/3
AC = 9 * 28/3 - 15
AC = 3 * 28 - 15
AC = 84 - 15
AC = 69
y=1/2x^2-4
Answer:
Step-by-step explanation:
This questions bothers permutation since permutation talks about arrangement.
The number of ways n objects can be arranged is n! ways
n! = n(n-1)(n-2)!
If a family of 5 is going on a cross-country vacation, and decided to change their seating arrangement. The total seating arrangement that they can have is;
5! = 5*4*3*2*1
5! = 20*6
5! = 120 different arrangements