Answer:
Let a = number of adult tickets sold
c = number of children's tickets sold
28a + 13c = 12,700---->28a + 13c = 12,700
a + c = 550------->13a + 13c = 7,150
--------------------------
15a = 5,550
a = 370, c = 180
370 adult tickets, 180 children's tickets
Let's solve this by using the quadratic formula:
Note that we only use the coefficients so a=12, b=-14, and c=-6.
Plug values in the quadratic equation:
And so by evaluating those values we obtain:
Now we have two answers which are our factors one where we add another where we subtract and so:
First factor:
Second Factor:
And so your factors are
meaning that those are your roots/x-intercepts.
false
a.
x less-than StartFraction 12 Over 7 EndFraction
b.
x less-than StartFraction 10 Over 3 EndFraction
c.
x less-than StartFraction 10 Over 7 EndFraction
d.
x less-than 4
The solution for the given inequality is x<4. Therefore, option D is the correct answer.
Given that, 5x-1<2x+11.
Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
Here, inequality 5x-1<2x+11 can be solved as follows
Add 1 on both the sides of inequality, we get
5x<2x+12
Subtract 2x on both the sides of inequality, we get
3x<12
Divide 3 on both the sides of inequality, we get
x<4
The solution for the given inequality is x<4. Therefore, option D is the correct answer.
To learn more about the inequalities visit:
brainly.com/question/20383699.
#SPJ2
Answer:
b. x less-than StartFraction 10 Over 3 End fraction
Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075