The difference between a histogram and a frequency polygon is The frequency polygon is reported as a percent. The histogram employs bars whereas the midpoints are connected for a frequency polygon. Bars cannot be adjacent in a histogram. Open-ended classes can be accommodated with a frequency polygon.

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Answer 1

Answer:

Answer: The frequency polygon is reported as a percent, providing a more intuitive understanding of the data distribution. In contrast, a histogram employs bars to represent the frequencies of different data intervals. Unlike a histogram, where bars cannot be adjacent to maintain clarity, a frequency polygon connects the midpoints of each interval, creating a smooth line. Also, a frequency polygon allows for the inclusion of open-ended classes, making it more flexible in representing data with varying ranges.

Step-by-step explanation:

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F(x)=-(x+2)²+2f(0)=-(0+2)²+2 = ??
f(1)=-(1+2)²+2 = ??
f(2)=-(2+2)²+2 = ??
f(3)=-(3+2)²+2 = ??
f(4)=-(4+2)²+2 = ??
Helpp

Answers

f(0)=-(0+2)²+2 = -1*(2)² + 2 = -4 + 2 = -2 y =-2
element of the set x = 0 attribute to an element of a set of y ( calculated y = -2 )
f(1)=-(1+2)²+2 = -1*(3)² + 2 = -9 + 2 = -7 y = -7
element of the set x = 1 attribute to an element of a set of y ( calculated y = -7 )
f(2)=-(2+2)²+2 = -1*(4)² + 2 = -16 + 2 = -14 y = -14
element of the set x = 2 attribute to an element of a set of y ( calculated y = -14 )
f(3)=-(3+2)²+2 = -1*(5)² + 2 = -25 + 2 = -23 y = -23
element of the set x = 3 attribute to an element of a set of y ( calculated y = -23 )
f(4)=-(4+2)²+2 = -1*(6)² + 2 = -36 + 2 = -34 y = -34
element of the set x = 4 attribute to an element of a set of y ( calculated y = -34 )

Answer:

f(0)=-(0+2)²+2 = -1*(2)² + 2 = -4 + 2 = -2 y =-2

element of the set x = 0 attribute to an element of a set of y ( calculated y = -2 )

f(1)=-(1+2)²+2 = -1*(3)² + 2 = -9 + 2 = -7 y = -7

element of the set x = 1 attribute to an element of a set of y ( calculated y = -7 )

f(2)=-(2+2)²+2 = -1*(4)² + 2 = -16 + 2 = -14 y = -14

element of the set x = 2 attribute to an element of a set of y ( calculated y = -14 )

f(3)=-(3+2)²+2 = -1*(5)² + 2 = -25 + 2 = -23 y = -23

element of the set x = 3 attribute to an element of a set of y ( calculated y = -23 )

f(4)=-(4+2)²+2 = -1*(6)² + 2 = -36 + 2 = -34 y = -34

element of the set x = 4 attribute to an element of a set of y ( calculated y = -34 )

1+3+5......+99 Si rezolvarea va rog fiindca nu inteleg !!

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I hope this helps you

Write a linear equation that passes through the point (2,-9) and has a slope of -5

Answers

Answer:

y = -5x + 1

Step-by-step explanation:

Given:

The slope m = -5 and point (2, -9)

Use point slope form:

y - y₁ = m(x - x₁), where (x₁, y₁) is the given point

So the equation is:

y - (-9) = -5(x - 2)
y + 9 = -5x + 10
y = -5x + 1

factor completely:

4x^3 - 36x

Answers

You would take out a 4x out of both terms because this is a common factor
4x^3-36x
4x(x^2-9)
and then you would notice that (x^2-9) is a difference of squares, so that factors out too
4x(x-3)(x+3)
that is all you can factor! hope this helps

the factor of this is 4x(x^2-9)
then x^2-9 can be factored using sum and difference.
4x(x+3)(x-3)

A = {0, 1, 2, 3}
B = {a, b, c, d}
C = {0, a, 2, b}

Find B n C.

Answers

So the n notation means what are in both of them so it would be {a, and B}

.072 ÷345.00 round nearest tenth

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this is calculatro problem
0.000209
to round to tenth,
look at hundreth place
0.00
rounded we get
0.0

answer is 0.0 since it is very small

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Pedro works as a newspaper deliverer. He receives a base pay plus an additional amount per newspaper delivered. Last week, Pedro delivered 5 newspapers and earned $37.50. This week, he delivered 20 newspapers and earned $75. Let x equal the number of newspapers Pedro delivers and y be the earnings he receives in dollars. Which linear function models the scenario?