On her bike, Katie can ride an average of 6 miles per hour. If she rides for one hour and thirty minutes, how far did she go? (Use proportions)

Answers

Answer 1

Answer:

Answer:

Katie went a distance of 9 miles.

Step-by-step explanation:

To find out how far Katie went when riding her bike for one hour and thirty minutes at an average speed of 6 miles per hour, you can use proportions.

First, you need to convert one hour and thirty minutes into hours. Since there are 60 minutes in an hour, one hour and thirty minutes is equivalent to:

1 hour + (30 minutes / 60 minutes) = 1.5 hours

Now that you know she rode for 1.5 hours at a speed of 6 miles per hour, you can set up a proportion to find the distance (d):

(1.5 hours / 1 hour) = (d miles / 6 miles per hour)

Now, cross-multiply and solve for d:

1.5 hours * 6 miles per hour = d miles

9 miles = d miles

Answer 2

Answer:

Answer:

9 mph

Step-by-step explanation:

proportion:

6/1 = x/1.5

use cross multiplication

1(x) = 6(1.5)

x = 9

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y 40 20 8 4

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I feel so stupid for not knowing the answer, please explain it to me.

Answers

x =   1, 2, 5, 10
y = 40,20, 8,   4

a) y = 40x
y = 40(1) = 40   ; y = 40(2) = 80 ;
y = 40(5) = 200 ; y = 40(10) = 400

b) y = (1/40)x ;
y = (1/40)1 = 1/40 ; y = (1/40)2 = 1/20 ;
y = (1/40)5 = 1/8 ; y =(1/40)10 = 1/4

c) xy = 40 ⇒ y = 40/x
y = 40/1 = 40 ; y = 40/2 = 20
y = 40/5 = 8 ; y = 40/10 = 4

Inverse variation. Choice C. xy = 40  is the correct answer.

HEY PLEASE HELP I AM DESPERATE I WILL GIVE YOU BRAINLIEST

Answers

y>/-4x+20

This is the answer :D

There are 11.5 ounces of cereal in a container. Additional cereal is poured into the container at a rate of 2.25 ounces per second. How many ounces are in the container after 4 seconds?

Answers

Answer:

13.........

Step-by-step explanation:

Solve 3x2 + 2x + 7 = 0. Round solutions to the nearest hundredth.(A)x ≈ −1.90 and x ≈ 1.23
(B)x ≈ −1.23 and x ≈ 1.90
(C)x ≈ −0.44 and x ≈ −3.56
(D)No real solutions

Answers

It is d work shown in the picture

Which congruence theorem can be used to prove ΔWXS ≅ ΔYZS?SAS

ASA

HL

SSS

Answers

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Answer:

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Step-by-step explanation:

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Answers

$\log_a (b * c)=\log_a b + \log_a c \n \log_a ((b)/(c))=\log_a b-\log_a c \n \log_a b^c=c \log_a b \n \n 1. \n \ln 6=\ln (2 * 3)=\boxed{\ln 2 + \ln 3} \approx 0.693+1.099=\boxed{1.792} \n \n 2. \n \ln ((10)/(3))=\ln ((2 * 5)/(3))=\boxed{\ln 2 + \ln 5 - \ln 3} \approx 0.693+1.609-1.099=\boxed{1.203} \n \n 3. \n \ln 30=\ln (2 * 3 * 5)=\boxed{\ln 2+ \ln 3 + \ln 5} \approx 0.693+ 1.099 + 1.609=\n=\boxed{3.401}$

$4. \n\ln 12=\ln (2^2 * 3)=\ln 2^2 + \ln 3=\boxed{2 \ln 2+ \ln 3} \approx 2 * 0.693+ 1.099= \n =\boxed{2.485} \n \n5. \n\ln ((2)/(5))=\boxed{\ln 2 - \ln 5} \approx 0.693-1.609=\boxed{-0.916} \n \n6. \n\ln ((5)/(6))=\ln ((5)/(2 * 3))=\ln 5-(\ln 2+ \ln 3)=\boxed{\ln 5 - \ln 2 - \ln 3} \approx \n\approx1.609-0.693-1.099=\boxed{-0.183}$

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