Answer:
3.00 moles
Explanation:
To calculate the number of moles of sulfur dioxide (SO2) in 192 grams of the gas, you can use the molar mass of SO2. Sulfur dioxide has a molar mass of approximately 64.0638 grams per mole.
Now, you can use the formula:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 192 g / 64.0638 g/mol ≈ 2.997 moles
So, there are approximately 3.00 moles of sulfur dioxide in 192 grams of the gas.
to block ultraviolet rays.
b.
to block infrared rays.
c.
to block glare from reflections (for example off lakes or roads).
d.
to look cool.
The primary purpose of polarized sunglasses is to block glare from reflections (for example off lakes or roads). The correct option is C.
Polarized sunglasses are a type of eyewear that has a special filter that blocks intense, reflected light and reduces glare. The filter is oriented vertically, allowing only the vertical component of light waves to pass through, while blocking the horizontal component. This reduces the glare from flat surfaces, such as water or snow, which can be distracting and even dangerous. Polarized sunglasses also enhance contrast and provide clearer vision, making them popular among athletes and outdoor enthusiasts. They are especially useful for activities such as fishing, boating, skiing, and driving. Polarized sunglasses can come in a variety of styles and lens colors, and can be worn in both prescription and non-prescription forms.
eEre in the Question,
Option a, to block ultraviolet rays, is true to some extent. Polarized sunglasses may have UV-blocking properties, but their primary purpose is not to block UV rays.
Option b, to block infrared rays, is not true. Polarized sunglasses are not designed to block infrared rays.
Option d, to look cool, is not true. While some people may wear polarized sunglasses for fashion purposes, their primary purpose is to reduce glare and improve visibility.
Therefore, The correct option is C. to block glare from reflections (for example off lakes or roads).
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-___________
B) Part of the strong magnet "rubs" off and joins to the paper clip.
C) The strong magnet aligns the magnetic domains within the paper clip.
D) The strong magnet creates an electric force filed around the paper clip.
When Lisa exposes an iron paper clip to a very strong magnet, the strong magnet aligns the magnetic domains within the paper clip and so, she is now able to pick up other paper clips using her newly magnetized clip.
The ends of the magnet, which are referred to as the poles, attract all of the iron filings when a small amount of it comes into contact with them. A magnet has two poles: an opposite pole and a similar pole. While unlike poles attract, like poles repel. When the distance between the two magnets is smaller, the magnetic force between them is larger.
Three different kinds of magnets exist:
Magnets are created when ferromagnetic elements, such as iron and nickel, are subjected to a magnetic field. Metals become permanently magnetic when heated to specific temperatures.
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Answer:
A) α = -1.228 rev/min²
B) 7980 revolutions
C) α_t = -8.57 x 10^(-4) m/s²
D) α = 21.5 m/s²
Explanation:
A) Using first equation of motion, we have;
ω = ω_o + αt
Where,
ω_o is initial angular velocity
α is angular acceleration
t is time the flywheel take to slow down to rest.
We are given, ω_o = 140 rev/min ; t = 1.9 hours = 1.9 x 60 seconds = 114 s ; ω = 0 rev/min
Thus,
0 = 140 + 114α
α = -140/114
α = -1.228 rev/min²
B) the number of revolutions would be given by the equation of motion;
S = (ω_o)t + (1/2)αt²
S = 140(114) - (1/2)(1.228)(114)²
S ≈ 7980 revolutions
C) we want to find tangential component of the velocity with r = 40cm = 0.4m
We will need to convert the angular acceleration to rad/s²
Thus,
α = -1.228 x (2π/60²) = - 0.0021433 rad/s²
Now, formula for tangential acceleration is;
α_t = α x r
α_t = - 0.0021433 x 0.4
α_t = -8.57 x 10^(-4) m/s²
D) we are told that the angular velocity is now 70 rev/min.
Let's convert it to rad/s;
ω = 70 x (2π/60) = 7.33 rad/s
So, radial angular acceleration is;
α_r = ω²r = 7.33² x 0.4
α_r = 21.49 m/s²
Thus, magnitude of total linear acceleration is;
α = √((α_t)² + (α_r)²)
α = √((-8.57 x 10^(-4))² + (21.49)²)
α = √461.82
α = 21.5 m/s²