What is the value of g[f(4)] for the functions f(x) = 3x-5 and g(x) = 2-x^2

Answers

Answer 1
Answer:

Answer:   -47

Work Shown

f(x) = 3x-5

f(4) = 3*4-5

f(4) = 12-5

f(4) = 7

We can then replace f(4) with 7 to go from g[ f(4) ] to g(7)

g(x) = 2 - x^2

g(7) = 2 - 7^2

g(7) = 2 - 49

g(7) = -47


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Pls help ASAP for brainliest answer

Answers

Answer:

324cm^3

Step-by-step explanation:

The formula for calculating volume of a triangular prism is 1/2× bhl (b : base, h : height, l : length)

1/2 × 6 × 9 × 12 = 324cm^3

How do you write 35 over 20 As a percentage

Answers

In order to write (35)/(20) as a percentage, we must first convert the fraction into a decimal. We can do that simply by dividing.

35 / 20 = 1.75

In order to convert a fraction to a decimal, we must multiply it by 100

1.75 * 100 = 175%

(35)/(20) as a percentage is 175%.
Hope that helped =)
Well, first you have to make it to a decimal, dividing 35 into 20, which is 1.75, and now you convert THAT into a percentage, which would be 175%, because we have to multiply it by 100.
I hope I helped! =D

Find the greatest common factor of 8, 6, and 10.
z

Answers

The Greatest Common Factor for 6, 8, and 10 is 2 because 2 can go into 6 three times, 2 can go into 8 four times, and 2 can go into 10 five times.
2 Factors of 8: 1, 2, 4, 8 Factors of 6: 1, 2, 3, 6 Factors of 10: 1, 2, 5, 10

Factoring polynomials of 18x-60x^5 please explain the steps.

Answers

rewrite as -60x^5 + 18x
factor out greatest common factor 6x
6x (-10x^4 + 3)

a chemist has two alloys, one of which is 10% gold and 15% lead and the other of which is 30% gold and 40% lead. how many grams of each of the two alloys should be used to make an alloy that contains 60 grams of gold and 88 grams of lead

Answers

Let the weight of the first alloy will be x grams.
Weight of gold will be 0.1x grams, weight of lead will be 0.15x grams.
Let the weight of the second alloy will be y grams.
Weight of gold will be 0.3y grams, weight of lead will be 0.4y grams.
Summarizing:
0.1x+0.3y=60       - gold
0.15x+0.4y=88     - lead

0.1x+0.3y=60     * 10   
0.15x+0.4y=88   * 100

x+3y=600          * 15
15x+40y=8800

15x+45y=9000      
15x+40y=8800

15x+45y=9000            /15
45y-40y=9000-8800

x+3y=600     
5y=200

x+3y=600     
y=40

y=40
x=600-3*40=480

y=40    
x=480

↑The answers.

What’s the result when 3a^2 - 2a + 5 is subtracted from a^2 + a - 1

Show all work

Answers

Answer:

-2a^2+3a-6

Step-by-step explanation:

a^2+a-1-(3a^2-2a+5)

=a^2+a-1-3a^2+2a-5

=-2a^2+3a-6