earth were now in synchronous rotation with the moon? that is, suppose that earth rotated at the same rate that the moon orbits earth. what would be differ-ent about earth and life on it?

Answers

Answer 1

Answer:

Answer:The day and night cycle would change bye 1.34 hours

Explanation:

Related Questions

A ship is able to float on water because it's density is less than that of the water.A. TrueB.False
Adding heat to a liquid causes which of the following physical changes?A. increases massB. increases densityC. decreases densityD. no physical change
Two waves with amplitudes of 75 units and 74 units arrive at a point in a medium simultaneously. If the two waves are out of phase with each other, what is the resultant amplitude of the wave?a. 74 units b. 1 unit c. 75 units d. m149 units
When you whisper, you produce a 10-dB sound.a. When you speak quietly, your voice sounds twice as loud as a whisper. How many decibels is this? b. When you speak normally, your voice sounds 4 times as loud as a whisper. How many decibels is this? c. When you yell, your voice sounds 8 times as loud as a whisper. How many decibels is this?
A train deports from a station at a constant acceleration of 5 m/s what is the speed of the train at the end of 20 seconds ?

Sally travels by car from one city to another. She drives for 30.0 min at 80.0 km/hr, 12.0 min at 105.0 km/hr, and 45.0 min at 40.0 km/hr, and she spends 15.0 min eating lunch and buying gas. A. Determine the average speed for the trip.
B. Determine the total distance traveled.

Answers

Answer:

A) The average speed for the trip is $v_(average) =53,53(km)/(h)$ .

B) The total distance traveled is $d_(total)=91\ km$ .

Explanation:

Knowing that 1 hour has 60 minutes, we have that for each part of the trip:

$v_(1)=80(km)/(h)\ t_(1)=0,5\ h$

$v_(2)=105(km)/(h)\ t_(2)=0,2\ h$

$v_(3)=40(km)/(h)\ t_(3)=0,75\ h$

$v_(4)=0(km)/(h)\ t_(4)=0,25\ h$

Total distance traveled

The distance traveled is the speed multiplied by a period of time. The total distance traveled is calculated adding up the speeds multiplied by the given periods of time.

$d_(total)=d_(1)+d_(2)+d_(3)$

$d_(total)=v_(1).t_(1)+v_(2).t_(2)+v_(3).t_(3)$

$d_(total)=80(km)/(h).0,5\ h+105(km)/(h).0,2\ h+40(km)/(h).0,75\ h$

$d_(total)=40\ km+21\ km+30\ km$

$d_(total)=91\ km$

B) The total distance traveled is $d_(total)=91\ km$ .

Average speed

The average speed could be calculated using the total distance traveled $d_(total)$ divided by the total time $t_(total)$ . We need to take into account the time spent eating lunch and buying gas.

$v_(average)=(d_(total))/(t_(total))$

$v_(average)=(v_(1).t_(1)+v_(2).t_(2)+v_(3).t_(3)+v_(4).t_(4))/(t_(1)+t_(2)+t_(3)+t_(4))$ $v_(average)=(91\ km)/(0,5\ h+0,2\ h+0,75\ h+0,25\ h)$

$v_(average)=(91\ km)/(1,70\ h)$

$v_(average)=53,53(km)/(h)$

A) The average speed for the trip is $v_(average) =53,53(km)/(h)$ .

Total distance = (30/60 x 80) + (12/60 x 105) + (45/60 x 40) = 0.5 x 80 + 0.2 x 105 + 0.75 x 40 = 40 + 21 + 30 = 91 km

Average distance = total distance / time taken = 91 / (30/60 + 12/60 + 45/60) = 91/ (0.5 + 0.2 + 0.75) = 91/1.45 = 62.76 km/hr

An elevator weighing 6,000 N moves up a distance of 10.0 meters in 30.0 seconds. a. How much work did the elevator’s motor do? b. What was the power of the elevator’s motor in watt and in horsepower?

Answers

Assume that work is equal to force x distance or w=fd. The force here is 6,000n and distance is 10.0 so therefore w=(6000n)(10.0m) and use that to do p=wt (power = work x time

Hypothesis and Data CollectionIn this experiment, you will evaluate the color and texture of salt, chalk, and talc and test their reactions in water and vinegar. Before you start the experiment, write down your predictions.

Part A
Which mineral will dissolve easily in water?