x = -1 are i& - i, but they are not sure how to use this information to solve for x in their
equation.
Part 1- Here is Hannah's work:
x? - 8x + 26 = 0
X? – 8x = -26
Show Hannah how
to finish her work using completing the square and complex numbers.
Part 2- Han decides to solve the equation using the quadratic
formula. Here is the beginning of his
work
-b+V62-4ac
-(-8)+7-8)2–401|(26)
Finish using the quadratic formula. Simplify the final answer as much as possible.
The solutions are:-
What is the equation?
The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.
Here given equation is
±
So,
Hence, the solutions are:-
To know more about the equation
#SPJ2
Part one:
Rewrite in the form
Solve
Solve
Part two:
Simplify
Separate solutions
Convert 976 cups to gallons.
Answer:
61 gallons
Step-by-step explanation:
16 cups per gallon: 976 cups/16 cups= 61 gallons
Answer:
61 gallons
Step-by-step explanation:
if you converted 976 cups to gallons, you would have 61 gallons.
P.S. your calculator should have volume calculations on it.
Answer:
Which statements did you include in your answer?
Isolate sin(x) by adding 4 and taking the square root of both sides.
State that sin(x) = 2 or sin(x) = –2.
State that –2 and 2 are undefined values of the inverse sine function.
There are no solutions because –2 and 2 are not in the domain of the function.
Step-by-step explanation:
Answer:
CA.
Step-by-step explanation:
To find the gradient (slope) of the line 2y - 3x = 6, we need to rewrite the equation in slope-intercept form (y = mx + b), where "m" represents the gradient. Here's how:
2y - 3x = 6
First, isolate "y" on one side of the equation:
2y = 3x + 6
Next, divide both sides by 2 to solve for "y":
y = (3/2)x + 3
Now we can see that the gradient (slope) of the line is (3/2).
Now, let's analyze the three lines AB, BC, and CA, formed by the points A(-5, -12), B(11, -4), and C(7, 6).
The gradient (slope) of the line AB can be calculated using the coordinates of points A and B:
Gradient of AB = (Change in y) / (Change in x) = (-4 - (-12)) / (11 - (-5)) = 8 / 16 = 1/2
The gradient (slope) of the line BC can be calculated using the coordinates of points B and C:
Gradient of BC = (Change in y) / (Change in x) = (6 - (-4)) / (7 - 11) = 10 / (-4) = -5/2
The gradient (slope) of the line CA can be calculated using the coordinates of points C and A:
Gradient of CA = (Change in y) / (Change in x) = (-12 - 6) / (-5 - 7) = -18 / (-12) = 3/2
Now, we compare the gradients of the lines AB, BC, and CA to the gradient of the line 2y - 3x = 6 (which is 3/2). We see that the line CA has the same gradient (3/2) as the line 2y - 3x = 6.
So, the line CA is parallel to the line 2y - 3x = 6.