ListenWhich statement has x = 2 as its solution?
3x - 12 = 17
7(x + 1) = 14
1- 6x = -11
4x + 5 = 3

Answers

Answer 1
Answer:

Answer: 1 - 6x = -11

Step-by-step explanation:

For each expression, substitute x for 2 to determine which is the correct expression:

3x - 12 = 17
3(2) - 12 = 17
6 - 12 = 17
-6 \neq 17
Because the number on the left side of the equation doesn't equal the number on the right, this first equation is incorrect.

7(x + 1) = 14
7(2 + 1) = 14
7(3) = 14
21 \neq14
This second equation is incorrect as well.

1 - 6x = -11
1 - 6(2) = -11
1 - 12 = -11
-11 = -11
Because the number on the left equals the number on the right, the third equation is correct.

I hope this helps! :)


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Hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. He spent a total of $47.65. Let m represent the number of magazines and b represent the number of books. Which equation models the situation?m + b = 47.95

m + b = 60.55

3.95m + 8.95b = 47.65

8.95m + 3.95b = 47.65

Answers

the third equation is true

3.95m+8.95b=47.65

good luck
Third equation is correct.

What is the equation of a line that is parallel to the line x=14 and contains the point (-3,7)?

Answers

Answer:

  x = -3

Step-by-step explanation:

The line x=14 is a vertical line. The line you want must also be a vertical line. In order for it to go through the given point, the constant in the equation must match the x-coordinate of the point: -3.

  x = constant . . . . equation of a vertical line

  x = -3 . . . . . . . . . . equation of your vertical line

if a scale map is 1 cm: 15 Km. find the actual distance corresponding to the scale map. 13) 2.5 cm 14) 0.2 cm 15) 15 cm 16) 4.6 cm

Answers

All you gotta do is multiply the cm by 15,
For 13) you'd do 2.5*15
14) 0.2*15 
15) 15*15
then for 16) 4.6*15

Let

x-------> distance in the map in cm

y-------> actual distance in Km

we know that

Scale\ Map=(x)/(y) \n \n Scale\ Map=(1)/(15)(cm)/(Km)

so

(x)/(y)=(1)/(15)

y=15x --------> equation 1

Part 13) find the actual distance corresponding to the scale map 2.5\ cm

In this problem we have

x=2.5\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*2.5=37.5\ Km

therefore

the answer part 13) is

the actual distance is 37.5\ Km

Part 14) find the actual distance corresponding to the scale map 0.2\ cm

In this problem we have

x=0.2\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*0.2=3\ Km

therefore

the answer part 14) is

the actual distance is 3\ Km

Part 15) find the actual distance corresponding to the scale map 15\ cm

In this problem we have

x=15\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*15=225\ Km

therefore

the answer part 15) is

the actual distance is 225\ Km

Part 16) find the actual distance corresponding to the scale map 4.6\ cm

In this problem we have

x=4.6\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*4.6=69\ Km

therefore

the answer part 16

the actual distance is 69\ Km

What is half of 1 litre

Answers

0.5 or 1/2 of a litre.

Compare using <, >, or =.

1/2 ___ 5/10

<
>
=

Answers

(1)/(2) = 0.5
(5)/(10) = 0.5

∴  (1)/(5) = (5)/(10)

Answer:

Step-by-step explanation:

1/2 = 0.5

5/10 = 0.5

So 1/2 = 5/10

Franks electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used. Approximately how many kilowatt-hours of electricity did frank use in March?

Answers

The power utilised by frank in the month of march is 470 kilowatts - per hour.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Franks's electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used.

The equation will be written as,

B = 20 + 0.14K

85.78 = 20 + 0.14k

k = ( 80.78 - 20 ) / 0.14

K = 65.78 / 0.14

K = 470 Kilowatt-hour

Therefore, the power utilised by frank in the month of march is 470 kilowatts - per hour.

To know more about an expression follow

brainly.com/question/17489069

#SPJ5

Answer:

I got 469.8 kilowatt-hours. I got this by taking the total of Frank's bill, which was $85.78, and subtracting the flat monthly fee of $20.00. I did this because I need to find out the number of kilowatt-hours Frank used. Then, I divided $65.78 by $0.14 since that is the price per kilowatt-hour and got about 469.8 kilowatt-hours used by Frank.