The 76 term of the arithmetic sequence 8, 14,20,

Answers

Answer 1
Answer:

Answer:

a76 = 8 + (76-1)*6

= 8 + 75*6

= 8 + 450

= 458

the 76th term of the arithmetic sequence 8, 14, 20 is 458


Related Questions

Inequality word problem 7 less than -2 times a number X is greater than or equal to 41
Which of the following is not a congruence transformation? A.Translating B.Rotating C.Dilating
Please Help me with this question
How do I write -2.5 into a fraction?
A candy machine is filled with candy. The weight of the candy can differ from the desired 84 ounce weight by no more than 0.5 ounces. Solve the absolute value equation given in order to find the heaviest and lightest acceptable weights for the candy machine.|x – 84| = 0.5

**For this question: you just have to come up w/ an equation.Jared has $3.85 in dimes and quarters. There are 25 coins in all. How many of each type of coin does he have?
Variables are: d (for dimes) and q (for quarters)

Answers

There's two actually.
0.25q + 0.10d = 3.85
q + d = 25

I need help with slope

Answers

We should know the slope formula:

m=(y2- y1)/(x2-x1)

Now plug in the points accordingly:
=(-1-4)/(1-(-4))
=(-5)/(5)

It can be simplified further:
(-5)/(5) = -1

Slope of the line that passes through (-4,4)  and (1,-1) is -1

A test has multiple choice questions with 5 choices for each answer; only one answer is correct for each question. Suppose a student guesses the answer to each question. Assuming the guesses are independent, find the probability that the student will not guess correctly on any one question.

Answers

First you have to define perimeters of Binomial distribution.

n - how many trials/questions do you have
p - probability guessing right answer to each question
x - how many successes do you expect.
Assuming the 6 questions are independent,
n=6 (questions)
p=probability of guessing the right answer (1/5)
x=exactly the number of successes over the 6 questions (2).

Look up the appendix table, or the Excel function to calculate the probability.

A train leaves the station at 9:00 pm traveling east at 36 miles per hour a second train leaves the station at 10:00 pm traveling west at 42 miles per hour at what time will both trains have traveled the same distance

Answers

Add the time they arrive at the common to individual starting points.
9.00 +(x)/(36) =10.00 + (x)/(42)
put the like terms together;
10.00 - 9.00=(x)/(36) - (x)/(42)
1=(42x-36x)/(36*42)
1=(6x)/(36*42)
6x=36*42
x=(36*42)/(6)
x=252 miles

What is 6P4?A.
30

B.
2

C.
24

D.
360

Answers

The answer would be 30 :)

Simplifiy (5x^2+3x-9)(2x-7)

Answers

(5x² + 3x - 9)(2x - 7)
5x²(2x - 7) + 3x(2x - 7) - 9(2x - 7)
5x²(2x) - 5x²(7) + 3x(2x) - 3x(7) - 9(2x) + 9(7)
10x³ - 35x² + 6x² - 21x - 18x + 63
10x³ - 29x² - 39x + 63