One positive number is 5 times another number. The difference between the two numbers is 200, find the numbers.

Answers

Answer 1

Answer: x = 5y, where x > 0 and y > 0;
x - y = 200 => 5y - y = 200 => 4y = 200 => y = 200/4 => y = 50 => x = 250.

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Solve each equation 7|9n+10|=70
Which answer correctly uses the distributive property to simplify the expression 6+4(3x-2)+5

Simplify 7N - 2N + 3P +2P

Answers

7n-2n+3p+2p
5n+5p (combine like terms)

the answer is 5n+5p

Combine like terms.
7N-2N=5N
3P+2P=5P
5N+5N

Simplify the expression: 1/1+cot^2xa.sec^2x
b.csc^2x
c.sin^2x
d.cos^2x
e.tan^2x

Answers

$\sin ^( 2 ){ x } +\cos ^( 2 ){ x } =1\n \n \frac { \sin ^( 2 ){ x } }{ \sin ^( 2 ){ x } } +\frac { \cos ^( 2 ){ x } }{ \sin ^( 2 ){ x } } =\frac { 1 }{ \sin ^( 2 ){ x } } \n \n 1+\cot ^( 2 ){ x } =\csc ^( 2 ){ x }$

Because of this...

$\frac { 1 }{ 1+\cot ^( 2 ){ x } } \n \n =\frac { 1 }{ \csc ^( 2 ){ x } }$

But...

$\frac { 1 }{ \csc ^( 2 ){ x } } =\sin ^( 2 ){ x }$

Therefore:

$\frac { 1 }{ 1+\cot ^( 2 ){ x } } =\sin ^( 2 ){ x }$

Answer:

(c)

Please 20 points like rn 5 mins left on test

Answers

Answer: counterclockwise rotation of 90° and a reflection over y axis

Step-by-step explanation:

How can i easily subtract and add a fraction?

Answers

line up the decmails up and add as usally

Line the decimals up and add like you normally would.But don't forget to put your decimal in your answer

A fence will be built to enclose a 100-m by 70-m field. It will need a post at each corner and one every 5 m. How many posts are needed?

Answers

The answer is 68.

Field had shape of rectangle since has difference in length and width. The perimeter of rectangle can be expressed as:
P = 2 × (a + b)

If:
a = 100 m
b = 70 m
Then
P = 2 × (100 m + 70 m)
P = 2 × 170 m
P = 340 m.

If posts are on every 5 m, the number of needed posts is:
340 m ÷ 5 m = 68.
Thus, 68 posts are needed for the fence.

F (x + 3)2 = 42, what is the approximate positive value of x? 0.48
3.48
5.48
6.48

Answers

Answer:

3.48

Step-by-step explanation:

I took the test.

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