mary made a small pan of ziti and a small pan of lasagna. she cut the ziti into 8 equal parts and the lasagna into 9 equal parts. her family ate 2/3 of the lasagna. if her family ate more lasagna than ziti what fraction of the ziti could have been eaten?

Answers

Answer 1

Answer:

Answer:

Hence, the possible fractions would be:

$(1)/(8),(2)/(8),(3)/(8),(4)/(8),(5)/(8)$

Step-by-step explanation:

" Mary made a small pan of ziti and a small pan of lasagna. she cut the ziti into 8 equal parts and the lasagna into 9 equal parts" .

Now her family ate 2/3 of the lasagna.

That means her family ate 6 lasanga. ( Since 2/3 of 9 parts is 6{ as (2\3)×9=6} ).

Now it is given that her family ate more lasagna than ziti.

i.e. her family would have eaten less than 6 ziti's.

I.e. they would have eaten either 1,2,3,4 or 5 ziti's.

Hence, the possible fractions would be:

$(1)/(8),(2)/(8),(3)/(8),(4)/(8),(5)/(8)$

Answer 2

Answer: Well, 2/3 times 9 is 6 parts of lasagna, so that means that the family must have eaten less than 6 piece of ziti; and 1/4 times 8 equals 2 parts of ziti...so 1/4 can be your answer!

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The sides of a square are 3 cm long. One vertex of thesquare is at (2,0) on a square coordinate grid marked in
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Answers

Answer: The required point that could also be a vertex of the square is K(5, 0).

Step-by-step explanation: Given that the sides of a square are 3 cm long and one vertex of the square is at (2,0) on a square coordinate grid marked in centimeter units.

We are to select the co-ordinates of the point that could also be a vertex of the square.

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Now, we will be suing the distance formula to calculate the lengths of the segment from the point to the vertex (2, 0).

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If the point is G(0, 1), then the length of the line segment will be

$\ell=√((0-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.$

If the point is H(1, -1), then the length of the line segment will be

$\ell=√((1-2)^2+(-1-0)^2)=√(1^2+1^2)=√(1+1)=\sqrt2~\textup{cm}\neq 3~\textup{cm}.$

If the point is J(4, 1), then the length of the line segment will be

$\ell=√((4-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.$

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$\ell=√((5-2)^2+(0-0)^2)=√(3^2+0^2)=√(3^2)=3~\textup{cm}.$

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K (5.0) It's easy just use 2plus3and that's it.

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Answers

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Answers

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