Answer:
Not a solution
Step-by-step explanation:
To determine if a pair of coordinates is the solution to an equation, just plug it in.
Given that the equation is:
y = 19x - 2
And the coordinates they give us to evaluate:
(6, 4)
Plug the coordinates in:
y = 19x - 2
4 = 19(6) - 2
4 = 114 - 2
4 = 112
4 ≠ 112
4 is not equal to 112. Therefore this pair is not the solution.
Explanation
The point (6,4) tells us that x = 6 and y = 4 pair up together.
Plug those values into the equation. Simplify both sides as much as possible (use PEMDAS). If we get the same thing on both sides, then that point is a solution to the equation.
y = 19x - 2
4 = 19*6 - 2
4 = 114 - 2
4 = 112
We get different values on each side. Therefore, the point (6,4) is not a solution to the equation.
Another approach you could do is graph the equation using a tool like Desmos. GeoGebra works as well. The point (6,4) is not on the diagonal line. Check out the diagram below to see what I mean.
Answer:
x = 3
Step-by-step explanation:
5x + 4 = 19
5x +4 -4 = 19 -4
5x = 15
5x / 5 = 15 / 5
x = 3
Answer:
see below
Step-by-step explanation:
You solve an equation by undoing what is done to the variable. When the variable is squared, as here, you undo the squaring by taking the square root. Any operation you do on one side of the equation must also be done on the other side. Hence, you take the square root of both sides of the equation.
10 2 7 3=16
11 8 17 4 =?
"? can be 19,30, 22 or 32"
84.8 in3
382 in3
215 in3
Answer: The correct option is (C) 382 in³.
Step-by-step explanation: Given that a regulation basketball has a diameter of about 9 inches.
We are to select the best approximation of the volume of the ball.
We know that basketball is of the shape of a SPHERE.
The VOLUME of a sphere with radius 'r' units is given by the formula:
The diameter of the basketball is about 9 inches, so its approximate radius will be
Therefore, the approximate volume of the basketball is
Thus, the best approximation of the volume of the ball is 382 in³.
Thus, (C) is the correct option.