Final Answer:
The complete combustion of fossil fuels and refuse produces D) carbon dioxide and water vapor.
Explanation:
Fossil fuels and refuse, when subjected to complete combustion in the presence of sufficient oxygen, undergo a chemical reaction. This reaction primarily produces carbon dioxide (CO2) and water vapor (H2O).
In summary, complete combustion of fossil fuels and refuse results in the production of carbon dioxide (CO2) and water vapor (H2O) as the primary products.
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The complete combustion of fossil fuels and refuse produces carbon dioxide and water vapor.
The complete combustion of fossil fuels and refuse produces carbon dioxide and water vapor. During combustion, the carbon in fossil fuels and refuse combines with oxygen from the air, resulting in the production of carbon dioxide (CO2) as the primary product. Additionally, hydrogen in the fuels and refuse combines with oxygen to form water vapor (H2O). This process releases energy in the form of heat and light.
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B. Jupiter
C. Mars
D. Neptune
Answer: Jupiter is believed to have prevented the asteroids in the asteroid belt from forming a planet.
methyl alcohol
ethyl alcohol
isopropyl alcohol
none of the above
B. 196 m
C. 260 m
D. 162.5 m
The Correct answer to this question for Penn Foster Students is: 137.5 m
1.998 ml of hydrogen gas volume is is required to react with 10.5 g of linolenic acid in this reaction.
Explanation:
Data given:
mass of linolenic acid is given = 10.5 grams
atomic mass of linoleinic acid = 278.43 grams/mole
volume of hydrogen required at STP = ?
Balance chemical reaction:
C18H30O2 + 3H2 --->C18H36O2
moles of linoleinic acid given =
putting the values in the equation:
moles of linoleinic acid =
= 0.037 moles
from the balanced equation:
1 mole of linoleinic acid reacts with 3 moles of hydrogen
so, 0.037 moles will react with x moles of hydrogen gas
=
x = 0.111 moles of water
volume or mass = atomic mass x number of moles
volume of hydrogen gas= 1.998 ml
Around 2.53 liters of hydrogen gas, at STP, is required to fully hydrogenate 10.5 g linolenic acid to stearic acid.
To solve this problem, we first need to find the molar mass of linolenic acid (C18H30O2). The molar mass is calculated by adding the molar masses of all the atoms in the molecule: (18*12.01) + (30*1.01) + (2*16.00) = 278.44 g/mol. Next, we calculate the number of moles of the linolenic acid we have: 10.5 g / 278.44 g/mol = 0.0377 mol. According to the balanced chemical equation, we need 3 mol of hydrogen per mol of Linolenic acid, so we need 0.0377 mol * 3 = 0.1131 mol of hydrogen gas. Finally, at STP, 1 mole of any type of gas occupies a volume of roughly 22.4 L, so the volume required is 0.1131 mol * 22.4 L/mol = 2.53 L.
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2. Calculate the moles of O in the sample.
Answer:
The answers are
C = 0.0895 moles
1. 0.02975 moles of N
2. 0.0299 moles O
Explanation:
Mass of sample = 2.18 g
Combustion yields 3.94 g of CO₂ and 1.89 g of H₂O
1.23 g of sample contains 0.235 g of N
3.94 g of CO₂ which contains one mole of C and two moles of O
Molar mass of CO₂ = 44 mass fraction of C = 12/44 = 0.273, Therefore mass of carbon in 2.18 g = 0.273×3.94 = 1.075 g
number of moles of C in sample = mass/(molar mass) = 1.075 g/(12.01 g/mol) = 0.0895 moles of C
(1) Mass of nitrogen, in 1.23 g of sample = 0.235
therefore mass in 2.18 g =0.235×2.18/1.23 = 0.4165 g
= 0.02975 moles of N
(2) To find the number of moles of oxygen in the sample we note that total mass of sample = 2.18 g containing only nitrogen, hydrogen, oxygen and carbon
Mass of hydrogen can be fround from 2/18×1.89 = 0.21 g
Mass of oxygen therefore = 2.18 -(0.21+0.4165+1.075) = 0.4785
number of moles = 0.475/16 = 0.0299 moles