MATHEMATICS HIGH SCHOOL

What value is 4 to the second power

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

4² = 4 × 4 = 16

Answer 2

Answer:

Answer:

4^2= 4*4 = 16 is the answer

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last night 80 people attended a lecture at the Smithfield Public Library 47th and 10 for men what ratio best represents the relationship between the number of men and the number of women

Answers

I encountered this question before. The correct phrasing of this question was:

Last night, 80 people attended a lecture at the Smithville Public Library. 47 of the attendees were men. What ratio BEST represents the relationship between the number of men and the number of women?

Given:
80 people
47 were men

80-47 = 33 number of women.

Number of men : 47
Number of women : 33

Ratio that best represents the relationship between the number of men and the number of women is 47 : 33.

PLEASE HELP If log a = b which of the following is true? (see attachment)

Answers

i wanna see the picture please so i can solve

Joline is solving the equation 0 = x2 – 5x – 4 using the quadratic formula. Which value is the negative real number solution to her quadratic equation? Round to the nearest tenth if necessary.

Answers

To solve a quadratic equation, we use the quadratic formula which is expressed as:

x1 = [-b + √(b²-4ac)] / 2a]
x2 = [-b - √(b²-4ac)] / 2a]

These formulas are used to solve for the values of the roots of the equation given. From the equation,

a = 1
b = -5
c = -4

Substituting the values, we have:

x1 = 5.70
x2 = -0.70

Therefore, the negative real number is -0.70.

The value -0.07 is the negative real number in the quadratic equation 0 = x² – 5x – 4

What is a quadratic equation ?

Any equation of the form $\rm ax^2+bx+c=0$ where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

$\rm x = (-b \pm√(b^2-4ac))/(2a)$

We have a quadratic equation;

0 = x² – 5x – 4 or

x² – 5x – 4 = 0

Here a = 1, b = -5, and c = -4

$\rm x = (-(-5) \pm√(-5^2-4(1)(-4)))/(2(1))$

$\rm x = (5 \pm√(41))/(2)$

After simplification:

x = 5.70 or x = -0.70

The value x = -0.70 is the negative real number.

Thus, the value -0.07 is the negative real number in the quadratic equation 0 = x² – 5x – 4

Learn more about quadratic equations here:

brainly.com/question/2263981

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Which type of sampling method is being employed in the following example? A study is being conducted of all schools in Gwinnett County. One student's parents from each school is randomly selected and asked in a survey what they think of Gwinnett County Public Schools.Simple Random Sampling

Stratified Sampling

Cluster Sampling

Sampling of Convenience

Systematic Sampling

Answers

Answer:

Stratified Sampling

Step-by-step explanation:

Stratified Sampling is a method of sampling that involves dividing a population into smaller groups. In the problem, one student's parents FROM EACHschool is randomly selected.

also..

I took the test and got 100% correct.

Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they areplanning on building. What is the approximate area covered by pavers Each square is 3
square feet

Answers

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

$A_((segment \, of \, semicircle)) = (1)/(4) * (\theta - sin\theta) * r^2$

Where:

$\theta = 2* tan^(-1)( (The \, number \, of \, vertical \, squrare \, sides \ cut \, by \ the \ large \, semicircle)/(The \, number \, of \, horizontal \, squrare \, sides \ cut \, by \ the \ large \, semicircle) )$