Answer:
((-6 + x)/2, (-8 + y)/2) = (-9, -11)
(-6 + x)/2 = -9 (-8 + y)/2 = -11
-6 + x = -18 -8 + y = -22
x = -12 y = -14
The other endpoint is (-12, -14).
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To find out how long it takes for the temperature of the roast to drop to 110 F, we can use the Newton's Law of Cooling equation. By setting up and solving a differential equation, we find that it takes approximately 34 minutes for the temperature of the roast to drop to 110 F.
To find out how long it takes for the temperature of the roast to drop to 110 F, we can use the Newton's Law of Cooling equation. This equation states that the rate of change of temperature of an object is proportional to the difference between its temperature and the temperature of its surroundings.
In this case, we can write the equation as: dT/dt = -k(T - Troom),
where dT/dt represents the rate of change of temperature with respect to time, T is the temperature of the roast, Troom is the temperature of the room, and k is a constant.
We know that when the roast was taken out of the oven, its temperature was 165 F, and after 15 minutes, its temperature dropped to 135 F. Using these values, we can set up the initial value problem:
dT/dt = -k(T - 70), T(0) = 165
Solving this differential equation, we find the value of k to be 1/15. Using this value, we can find the time it takes for the temperature to drop to 110 F:
dT/dt = -1/15(T - 70)
Integration of the equation gives: ln|T - 70| = -t/15 + C
Using the initial condition T(0) = 165, we can find the value of the constant C as: ln|165 - 70| = 0 + C
Therefore, C = ln(95).
Substituting back into the equation, we get:
ln|T - 70| = -t/15 + ln(95)
T - 70 = e^(-t/15 + ln(95))
T = 70 + 25e^(-t/15)
Now, we can substitute T = 110 and solve for t:
110 = 70 + 25e^(-t/15)
25e^(-t/15) = 40
e^(-t/15) = 40/25
-t/15 = ln(40/25)
t = -15ln(40/25)
Simplifying, we find that it takes approximately 34 minutes for the temperature of the roast to drop to 110 F.
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Factοring is the prοcess οf reversing the distributive prοperty sο that a pοlynοmial can be written as the prοduct οf simpler pοlynοmials is true.
Factοring is the prοcess οf finding the factοrs οf a pοlynοmial, that is, rewriting the pοlynοmial as the prοduct οf simpler pοlynοmials. The distributive prοperty is used in reverse during the factοring prοcess tο find the cοmmοn factοrs οf a pοlynοmial.
Fοr example, cοnsider the pοlynοmial expressiοn . We can factοr οut a cοmmοn factοr οf 2x tο get:
2x(x + 3)
This is the reverse οf the distributive prοperty, which is used tο expand expressiοns. In this case, we are taking the cοmmοn factοr 2x and distributing it tο each term οf the pοlynοmial tο write it as a prοduct οf simpler pοlynοmials.
Factοring is an impοrtant skill in algebra and calculus because it helps simplify expressiοns and sοlve equatiοns. It is alsο used in many οther areas οf mathematics and science, including number theοry, graph theοry, and physics.
Learn more about factoring on:
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x =
!/5x1/5 =2/5
!/5 one possible of the total of 5
Multiply both