Alexis can type 35 words in a minute. her friend Jonathan can type 40 words in a minute. How long will it take Alexis to type 140 words?
Answers
Answer:
a situation of proportionality is assumed
35 words 140 words
1min(1*140)/35=4min
it takes 4min to type 140 words
Step-by-step explanation:
Related Questions
A rectangular field is 80 meters wide and 125 meters long.Give the length and width of another rectangular field that has the same perimeter but a smaller area.
The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.Which function equation represents the population of the pack of wolves after t years?f(t)=88(0.025)^tf(t)=88(1.025)^tf(t)=88(1.25)^tf(t)=88(2.5)^t
Compare new france and the 13 colonies in the terms of population, government and economy
I need some help with this problem
Answers
Answer:
Step-by-step explanation:
Total number of hits by baseball player in one season = 61
Number of hits in one game =
To find:
The expression to represent the number of hits that the player got in the rest of the games = ?
Solution:
Number of hits that the player got in one game =
Let the number of hits that the player got in rest of the games =
As per the given question statement,
The sum of and
will be equal to 61.
Therefore, the player had hits in the rest of the games.
A)x = 4
B)x = -4
C)x = ±4
D)No Solution
Answers
First, take the square root to both sides.
Second, now we have 4 × 4 which is 16, meaning the square root of 16 is 4.
Third, there are two solutions.
Fourth, since we have two values, it is reasonable to use the plus-minus sign to indicate there is a positive and a negative solution.
Answer: C) x = ±4
x = √16
x = 4.
so the answer is A. x = 4.
Answers
1 box = 6 bags
11 boxes = 6 x 11
11 boxes = 66 bags
1 bag = 45 marbles
66 bags = 45 x 66
66 bags = 2970 marbles
Answer: The shop ordered 2970 marbles.
Answers
Thank you.
Answer:
The vertical asymptote of a function secant are determined by the points that are not in the domain.
Step-by-step explanation:
The domain of a function is the set of x values for which the function is defined.
Secant function is not defined at
It means we cannot include these points in the domain.
At these points, we must have a vertical line which do not touch the graph. These lines are called "Vertical asymptotes"
Vertical asymptotes are not included in the domain of the function.
Hence, the correct word should be "Asymptote"
The vertical asymptote of a function secant are determined by the points that are not in the domain.
Answers
x-(-y) means x+y since minusing a negative cancels
-3z^7+5z^7
addthe coeficients
one way to show is undistribute
-3z^7+5z^7=(z^7)(-3+5)=(z^7)(2)=2z^7
answer is 2z^7
Answers
Answer:
a) the probability of waiting more than 10 min is 2/3 ≈ 66,67%
b) the probability of waiting more than 10 min, knowing that you already waited 15 min is 5/15 ≈ 33,33%
Step-by-step explanation:
to calculate, we will use the uniform distribution function:
p(c≤X≤d)= (d-c)/(B-A) , for A≤x≤B
where p(c≤X≤d) is the probability that the variable is between the values c and d. B is the maximum value possible and A is the minimum value possible.
In our case the random variable X= waiting time for the bus, and therefore
B= 30 min (maximum waiting time, it arrives 10:30 a.m)
A= 0 (minimum waiting time, it arrives 10:00 a.m )
a) the probability that the waiting time is longer than 10 minutes:
c=10 min , d=B=30 min --> waiting time X between 10 and 30 minutes
p(10 min≤X≤30 min) = (30 min - 10 min) / (30 min - 0 min) = 20/30=2/3 ≈ 66,67%
a) the probability that 10 minutes or more are needed to wait starting from 10:15 , is the same that saying that the waiting time is greater than 25 min (X≥25 min) knowing that you have waited 15 min (X≥15 min). This is written as P(X≥25 | X≥15 ). To calculate it the theorem of Bayes is used
P(A | B )= P(A ∩ B ) / P(A) . where P(A | B ) is the probability that A happen , knowing that B already happened. And P(A ∩ B ) is the probability that both A and B happen.
In our case:
P(X≥25 | X≥15 )= P(X≥25 ∩ X≥15 ) / P(X≥15 ) = P(X≥25) / P(X≥15) ,
Note: P(X≥25 ∩ X≥15 )= P(X≥25) because if you wait more than 25 minutes, you are already waiting more than 15 minutes
- P(X≥25) is the probability that waiting time is greater than 25 min
c=25 min , d=B=30 min --> waiting time X between 25 and 30 minutes
p(25 min≤X≤30 min) = (30 min - 25 min) / (30 min - 0 min) = 5/30 ≈ 16,67%
- P(X≥15) is the probability that waiting time is greater than 15 min --> p(15 min≤X≤30 min) = (30 min - 15 min) / (30 min - 0 min) = 15/30
therefore
P(X≥25 | X≥15 )= P(X≥25) / P(X≥15) = (5/30) / (15/30) =5/15=1/3 ≈ 33,33%
Note:
P(X≥25 | X≥15 )≈ 33,33% ≥ P(X≥25) ≈ 16,67% since we know that the bus did not arrive the first 15 minutes and therefore is more likely that the actual waiting time could be in the 25 min - 30 min range (10:25-10:30).