Answer:
The difference of height is 10 cm
Step-by-step explanation:
Monte performs an experiment using 2 identical graduated cylinders with a radius of 2 cm.
The volume of the liquid in the first graduated cylinder is 188.4 cm³
The volume of the liquid in the second graduated cylinder is 314 cm³
Let height of first graduated cylinder be h₁ and radius (r) = 2 cm
Let height of second graduated cylinder be h₂ and radius (r) = 2 cm
Formula:
cm
cm
The difference in the height of the liquid in two cylinder,
cm
Hence, The difference of height is 10 cm
up a proportion to model this situation. How much did you spend this month?
Set up a proportion to model this situation. Choose the correct answer below
Answer:
This month you spent $60
50 x
__ = __
1 1.2
120% of 50 would be 60.
this is how you solve for x;
5x + 10 = -4x -17
5x + 4x + 10 = -4x +4x -17 (add 4x on both sides)
9x + 10 = -17
9x +10-10 = -17 -10 (subtract 10 on both sides)
9x = - 27 (next do the inverse operation of x)
x = -27 ÷ 9
x = -3
Answer:
Total length of ribbon to line the long sides will be 22 in
Step-by-step explanation:
In the given figure of kite if we draw a line "h" vertically will form two right angle triangles.
Then by applying Pythagoras theorem in both the triangles.
h²= (3x + 5)² + (2x + 1)² ------(1)
h²= (5x + 1)² + 5² ------(2)
By equating both the equations
(3x + 5)² + (2x + 1)² = (5x + 1)² + 25
9x² + 25 + 30x + 4x² + 4x + 1 = 25x² + 10x + 1 + 25
13x² + 34x + 26 = 25x² + 10x + 26
13x² - 25x² + 34x - 10x + 26 - 26 = 0
- 12x² + 24x = 0
12x² - 24x = 0
x² - 2x = 0
x(x - 2) = 0
x = 2
Now we will put x = 2 in the measure of sides of the kite.
Side 1 = (3x + 5)
= 3×2 + 5
= 11
Side 2 = (5x + 1)
= 5×2 + 1
= 11
Side 3 = (2x + 1)
= 2×2 + 1
= 5
Therefore, Total length of ribbon to line the long sides will be = 11 + 11
= 22 in.
Your answer will be D-22.