What two numbers add up to -15 & can be multiplied to get 56

Answers

Answer 1

Answer: -8 and -7, I used guess and check

Answer 2

Answer: -8 and -7,because when you add those two numbers,you get -15 because their both negative numbers,and iff you multiply them,they equal 56 because negative times a negative equals a positive.ur welcome!:)

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At the beginning of each year, Bill Ross invests $1,400 semi-annually at 8 percent for 9 years. The cash value of the annuity due at the end of the ninth year is: ...?

Answers

The correct answer would be D. $37,339.68.

To solve this,
$1,400 x 27.6712 = $38,739.68 - 1,400.00 = $37,339.18

This is what the cash value of the annuity due at the end of the ninth year is if Bill Ross invests $1,400 semi-annually at 8 percent for 9 years.

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.

A certain bacteria population is known to quadruples every 150 minutes. Suppose that there are initially 200 bacteria. What is the size of the population after t hours?

Answers

This is a geometric progression
The size of the population afeter t hours will be=a₁*r^n

a₁= the first term =200
r=common ratio=4

150 minutes=150 minutes * (1 hour /60 minutes)=2.5 hours.

In this case:
the size of the populatation after t hours=200*4^t/2.5=200*4^0.4t

To check
t=0⇒ the size will be=200*4⁰=200*1=200
t=2.5 hours=150 minutes; the size will be =200*4¹=800
t=5 hours; the size will be=200*4²=200*16=3200

Answer: the size will be= 200*4^(0.4t)

Final answer:

The growth of the bacteria is represented by the exponential growth equation. Given the initial population, the four-fold increase, and the time interval for the increase, we can find the population after any given time by using the equation P = 200 * 4^(t/2.5).

Explanation:

The problem given is an example of an exponential growth problem. For these types of problems, we use the formula P = P0 * e^(kt), where P is the final population, P0 is the initial population, k is the growth rate, and t is time. However, in this case, we were given that the bacteria quadruples, meaning 'quadrupling' is not a continuous rate, so we use a slightly different form of the equation: P = P0 * (b)^(t/t0), where b is the times increase and t0 is the time interval for the b-fold increase.

Given that the initial population P0 is 200 bacteria, b is 4 because the population quadruples every 150 minutes, and time t0 is 150 minutes or 2.5 hours. We need to find the population P after t hours. Substituting these values into our equation gives us: P = 200 * 4^(t/2.5).

So, after t hours, the population of the bacteria will be given by the equation P = 200 * 4^(t/2.5).

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A=(s-2)180 solve for s

Answers

You said that    A = (s-2) 180

Divide each side by 180 : A/180    = s-2

Add 2 to each side:     A/180 + 2 = s

A = (s - 2)180

A = (s)180 - (2)180

A = 180s - 360 (add 360 to each side)

A + 360 = 180s - 360 + 360

A + 360 = 180s (divide 180 from each side)

(A + 360)/180 = s

s =

What is the answer to this question?

Answers

angle GDH and angle FDE

The line y =3x-5 meet x-axis at the point M. The line 3y+2x=2 meets y-axis at point N. Find the equation of the line joining M and N in the form ax + by + c = 0 where: a,b,c are integers.

Answers

Answer-

The line equation is,

$\boxed{\boxed{6x+15y-10=0}}$

Solution-

The line $y =3x-5$ meets x-axis at the point M, i.e M is the x-intercept of this line. At the x-intercept y=0, so

$\Rightarrow 0 =3x-5$

$\Rightarrow 3x=5$

$\Rightarrow x=(5)/(3)$

So, coordinate of M is $((5)/(3),\ 0)$

The line $3y+2x=2$ meets y-axis at point N, i.e N is the y-intercept of this line. At the y-intercept x=0, so

$\Rightarrow 3y+2(0)=2$

$\Rightarrow 3y=2$

$\Rightarrow y=(2)/(3)$

So, coordinate of N is $(0,\ (2)/(3))$

The line joining M and N can be found out by applying two point formula of straight line,

$\Rightarrow (y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)$

$\Rightarrow (y-0)/((2)/(3)-0)=(x-(5)/(3))/(0-(5)/(3))$

$\Rightarrow (y)/((2)/(3))=(x-(5)/(3))/(-(5)/(3))$

$\Rightarrow -(5)/(3)y=(2)/(3)(x-(5)/(3))$

$\Rightarrow -5y=2(x-(5)/(3))$

$\Rightarrow -5y=2x-(10)/(3)$

$\Rightarrow 2x+5y-(10)/(3)=0$

As it is given that all the coefficients are integers, so multiplying with 3

$\Rightarrow 6x+15y-10=0$

Solution: As given line y =3x-5 meet x-axis at the point M.

On x axis y coordinate is zero.

Put y =0 in above equation, we get →x = 5/3

∴ Coordinate of M is (5/3,0).

As, also given , line 3y+2x=2 meets y-axis at point N.

On y axis , x coordinate is zero.

Substituting , x=0 in above equation, gives y =2/3.

Coordinate of point N is (0,2/3).

Equation of line passing through two points (a,b) and (p,q) is given by

→ $(y-b)/(x-a) =(q-b)/(p-a)$

Or as X intercept = 5/3, and Y intercept = 2/3

Equation of line in intercept form is → $(x)/(a) + (y)/(b) =1$ , where a and b is X intercept and y intercept respectively.

So, line passing through (5/3,0) and (0,2/3) is given by

→ $(x)/((5)/(3)) + (y)/((2)/(3))=1$

→ $(3x)/(5) + (3y)/(2) =1$

→ 6 x + 15 y =10 [Taking LCM of 5 and 2 which is 10]

→ 6 x + 15 y -10=0, which is equation of the line joining M and N in the form ax + by + c = 0 where: a,b,c are integers.

Are the graphs of y=3/8x -5 and y=3/8x +2 parallel?

Answers

The graph of y = (3/8)x - 5 and y = (3/8)x + 2 are parallel since both graphs have the same slope.

What is an equation of a line?

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

The graph of two equations is parallel if the slope of each of the equations is the same.

The two equations are:

y = (3/8)x - 5 _____(1)

y = (3/8)x + 2 _____(2)

This is in the form of y = mx + c

Where m is the slope.

Now,

From (1 ) and (2) we see that,

m = 3/8

Thus,

The graphs are parallel.

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yes because they have the same slope of 3/8

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