How to solve 2+1/6a=-4

Answers

Answer 1

Answer: $2+ (1)/(6a) =-4\Leftrightarrow 6+(1)/(6a)=0\Rightarrow 36a=-1\Rightarrow a=-1/36$

Answer 2

Answer: $2+ (1)/(6)a=-4$

$(1)/(6)a=-6$

$1a=-6*6$

$a=-36$

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After school, Hannah works for 2.8 hours a day, 4 days a week. If her hourly wage is $9.12, how much does shemake each week, rounded to the nearest cent?

Answers

Answer:

$102.14

Step-by-step explanation:

2.8 hours a day X 4 days = 11.2

11.2 X $9.12 = 102.144

rounded to the nearest cent is $102.14

Help me answer this plz I really need help

Answers

Answer:

E (b/3) +3

Step-by-step explanation:

3c =b

c+3 = ?

Solve the first equation for c

3c=b

Divide by 3

3c/3 = b/3

c = b/3

Now replace c with b/3 in c+3

c+3

(b/3) +3

Answer:

Answer E. is correct

Step-by-step explanation:

b = 3 * c --> c = 1/3 * b

c + 3 = 1/3 * b + 3 --> E.

Solve for each expression by writing the solution in unit form and in standard form 6 ten thousands divided by 10

Answers

Solve the given equation by writing the solution inUnit form and Standard form.
Given equation = 6 ten thousands divided by 10

Unit form – place Value form
=> 6 ten thousands
=> divided = /
=10 or 1 tens
=> 6 ten thousands / 1 tens
=> 6 thousands

Standard form- Numerical form
=> 6 ten thousands = 60 000
=> divided = /
=> 10
=> 60 000 / 10
=> 6000

Thus, the answer of 6 ten thousands divided by 10 is equals to 6000

What is the correct sums 7 hundredths + 7 tenths ，7 tenths + 70 hundredths
，1 tenth + 17 hundredths
，10 tenths + 4 hundredths
，11 hundredths + 8 tenths

，Options 177\100 91\100 140\100 77\100 27\100 104\100

Answers

$a) (7)/(100) + (7)/(10) = (7)/(100) + (7*10)/(10*10) = (7+70)/(100) = (77)/(100) \n \n b) (7)/(10) + (70)/(100) = (7*10)/(10*10)+ (70)/(100)= (70+70)/(100)= (140)/(100) \n \n c)(1)/(10) + (17)/(100) = (1*10)/(10*10) + (17)/(100)= (10+17)/(100) = (27)/(100) \n \n d) (1)/(1) + (4)/(00) =(1*100)/(1*100) + (4)/(100) = (100)/(100) + (4)/(100) = (104)/(100) \n \n$

$e) (11)/(100)+ (8)/(10) = (11)/(100)+(8*10)/(10*10) =(11+80)/(100) = (91)/(100)$

100 POINTS HELP PLEASEEEE !!!HURRY!!!

Answers

Question # 1 Solution

Answer:

$(h-f)(-8)=-229$

Step-by-step Solution:

Given

$h(r)=-4r^(2)+4$

$f(r)=2r-7$

$(h-f)(r)=h(r)-f(r)$

$(h-f)(r)=-4r^(2)+4-(2r-7)$

$(h-f)(r)=-4r^(2)+4-2r+7)$

We have to find $(h-f)(-8)$

So,

$(h-f)(-8)=-4(-8)^(2)+4-2(-8)+7)$

$(h-f)(-8)=-4(64)+4+16+7$

$(h-f)(-8)=-256+4+16+7$

$(h-f)(-8)=-229$

∴ $(h-f)(-8)=-229$

Question # 2 Solution

Answer:

∴ $(f.p)(9)=38979$

Step-by-step Solution:

Given

$f(s)=7s-2$

$p(s)=s^(3)-10s$

$(f.p)(s)=f(s).p(s)$

$(f.p)(s)=(7s-2)(s^(3)-10s)$

$(f.p)(s)=7s^4-2s^3-70s^2+20s$

We have to find $(f.p)(9)$

So,

$(f.p)(9)=7\left(9\right)^4-2\left(9\right)^3-70\left(9\right)^2+20\left(9\right)$

$(f.p)(9)=7\cdot \:9^4-2\cdot \:9^3-70\cdot \:9^2+20\cdot \:9$

$(f.p)(9)=9^4\cdot \:7-9^3\cdot \:2-9^2\cdot \:70+180$

$(f.p)(9)=45927-1458-5670+180$

$(f.p)(9)=38979$

∴ $(f.p)(9)=38979$

Question # 3 Solution

Answer:

$((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

Step-by-step Solution:

Given

$p(r)=r^(3)+6r$

$f(r)=11r+8$

We have to find $((f)/(p))(r)$

Using the formula

$((f)/(p))(r)=(f(r))/(p(r))$

$p(r)=r^(3)+6r$

$f(r)=11r+8$

$((f)/(p))(r)=(11r+8)/(r^(3)+6r)$

$((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

∴ $((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

Question # 4 Solution

Answer:

$(h-p)(k)=5k^2-3-k^3-8k$

Step-by-step Solution:

Given

$h(k)=5k^(2)-3$

$p(k)=k^(3)+8k$

We have to find $(h-p)(k)$

Using the formula

$(h-p)(k)=h(k)-p(k)$

$h(k)=5k^(2)-3$

$p(k)=k^(3)+8k$

$(h-p)(k)=5k^(2)-3-(k^(3)+8k)$

$(h-p)(k)=5k^2-3-k^3-8k$

∴ $(h-p)(k)=5k^2-3-k^3-8k$

Question # 5 Solution

Answer:

$((p)/(g))(11)=(1287)/(155)$

Step-by-step Solution:

Given

$p(b)=b^(3)-4b$

$g(b)=b^(2)+4b-10$

We have to find $((p)/(g))(11)$

$((p)/(g))(b)=(p(b))/(g(b))$

$((p)/(g))(b)=(b^(3)-4b)/(b^(2)+4b-10)$

$((p)/(g))(11)=(11^(3)-4(11))/(11^(2)+4(11)-10)$

$((p)/(g))(11)=(1287)/(155)$

∴ $((p)/(g))(11)=(1287)/(155)$

Question # 6 Solution

Answer:

$(f+g)(x)=x^2+20x-18$

Step-by-step Solution:

Given

$g(x)=x^(2)+11x-7$

$f(x)=9x-11$

We have to find $(f+g)(x)$

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=9x-11+(x^(2)+11x-7)$

$(f+g)(x)=9x-11+x^(2)+11x-7$

$(f+g)(x)=x^2+20x-18$

∴ $(f+g)(x)=x^2+20x-18$

Question # 7 Solution

Answer:

$h(10)+g(10)=-983$

Step-by-step Solution:

Given

$h(w)=-11w^(2)-7$

$g(w)=w^(2)+3w-6$

We have to find $h(10)+g(10)$

So,

$h(10)=-11(10)^(2)-7$

$h(10)=-1107$ .....[1]

and

$g(10)=10^(2)+3(10)-6$

$g(10)=124$ .....[2]

Adding Equation [1] and Equation [2]

$h(10)+g(10)=-1107+124$

$h(10)+g(10)=-983$

∴ $h(10)+g(10)=-983$

Question # 8 Solution

Answer:

$(f+g)(-3)=-6$

Step-by-step Solution:

Given

$g(b)=b^(2)+9b+10$

$f(b)=3b+11$

We have to find $(f+g)(-3)$

$(f+g)(b)=f(b)+g(b)$

$(f+g)(b)=3b+11+b^(2)+9b+10$

$(f+g)(-3)=3(-3)+11+(-3)^(2)+9(-3)+10$

$(f+g)(-3)=-6$

∴ $(f+g)(-3)=-6$

Question # 9 Solution

Answer:

$(f.h)(k)=33k^3+22k-12k^2-8$

Step-by-step Solution:

Given

$f(k)=-11k+4$

$h(k)=-3k^(2)-2$

We have to find $(f.h)(k)$

$(f.h)(k)=f(k).h(k)$

So,

$(f.h)(k)=(-11k+4).(-3k^(2)-2)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

∵ FOIL means (First, Outer, Inner, Last)

$(f.h)(k)=\left(-11k\right)\left(-3k^2\right)+\left(-11k\right)\left(-2\right)+4\left(-3k^2\right)+4\left(-2\right)$

$(f.h)(k)=33k^3+22k-12k^2-8$

∴ $(f.h)(k)=33k^3+22k-12k^2-8$

Question # 10 Solution

Answer:

$p(-8)-f(-8)=-581$

Step-by-step Solution:

Given

$p(s)=s^(3)+6s$

$f(s)=-2s+5$

We have to find $p(-8)-f(-8)$

So,

$p(-8)=(-8)^(3)+6(-8)$

$p(-8)=-560.....[1]$

and

$f(-8)=-2(-8)+5$

$f(-8)=21.....[2]$

Subtracting Equation [2] from Equation [1]

$p(-8)-f(-8)=-560-21$

$p(-8)-f(-8)=-581$

∴ $p(-8)-f(-8)=-581$

Keywords: function operation

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Answer:

-2229

Step-by-step explanation:

Plz help i'm stuck !!!!!!!!!

Answers

first, you should add -1 on both sides of the equation so yu will have:
9 - 1 ≤ c so 8 ≤ c
now if you wanna show it in the graph you should put a dark dot on 8 and graph a line up to the 8 so your graph is the second one (under the pic) :))
I hope this is helpful
have a nice day

i think its the filled circle pointing this way --->

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