Answer:
1o
Step-by-step explanation:
By following steps given, you can successfully placed the fraction 5/2 on the number line.
To put the fraction 5/2 on a number line, you can follow these steps:
1) Draw a straight line horizontally on a piece of paper or use a number line chart if available. Make sure the line is long enough to accommodate the desired range.
2) Determine the range you want to represent on the number line. Let's say you want to represent the numbers from 0 to 3.
3) Divide the line into equal segments to match the range you determined.
For example, you can divide the line into four equal segments representing the numbers 0, 1, 2, and 3.
4) Locate the whole number part of the fraction, which is 2 in this case. Place a point or tick mark above the number 2 on the number line.
5) Divide the segment between the whole numbers into equal parts. Since the fraction is 5/2, you need to divide the segment between 2 and 3 into two equal parts.
6) Starting from the point above the number 2, count two equal segments to the right.
Place a tick mark or point at the end of the second segment.
7) Label this point with the fraction 5/2.
Learn more about number line click;
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The coordinates of vertex B′ are ____ .
The coordinates of vertex C′ are ____.
Answer:
A'(1, 1); B'(3, 2); C'(1, 2)
Step-by-step explanation:
The original points are A(1,1 ), B(2, 3) and C(2, 1).
Reflecting the triangle across the x-axis will negate every y-coordinate; this maps
(1, 1)→(1, -1); (2, 3)→(2, -3); (2, 1)→(2, -1)
Rotating the figure 90° clockwise about the origin switches the x- and y-coordinates and negates the x-coordinate; this maps
(1, -1)→(-1 -1); (2, -3)→(-3, -2); (2, -1)→(-1, -2)
Reflecting across the line y=x will negate both the x- and y-coordinates; this maps
(-1, -1)→(1, 1); (-3, -2)→(3, 2); (-1, -2)→(1, 2)
To find the coordinates of ∆ABC after reflection across the x-axis, rotation by 90°, and reflection across y = x, we would apply these transformations to each point. Initially reflected across x-axis results in (x, -y), the 90° rotation gives (-y, x), and final reflection over y = x gives (x, -y). To find A′B′C′ we would need original coordinates, but general rule follows this pattern.
In this mathematics problem, we will find the coordinates for vertex A′, B′, and C′ of ∆A′B′C′. Given a triangle ∆ABC reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the line y = x, we need the original coordinates of A, B, and C to find A′B′C′. However, if we take a generic point (x, y), we can assume the following:
Assuming these transformations, we can find the final coordinates for A′, B′, and C′.
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In algebraic expression would I have an + sign or??
Answer:
loan 2 on the first one and loan 1 on the second one
Answer:
loan 2 for number 3
and
loan 1 for number 4
if you look at the interest, time it takes to pay it off, and how much you'd have to pay each month you normally can tell which one is the better deal. :)
Answer:
The dimension of the farm are 35 by 25 meters
Area of farm = 750 sq. m
110 meters will be the perimeter
let one side be x
the other side will be 110-2x /2
Area = L * W
x((110-2x /2)=750
x(110-2x /2 ) =750
110x-2x^2/ 2 =750
110x-2x^2= 1500
2x^2-110x+1500=0
x^2-55x+750=0
x^2-30x-25x+750=0
x(x-30)-25(x-30)=0
(x-30)(X-25)=0
x= 30 OR 25
I really hope this helps you and sorry for the late response :)
To find the dimensions of the rectangular farm, you'd set up two equations based on the given area and perimeter, and solve them to find the values of the length and width.
To solve this problem, you need to use the concept of area and perimeter in mathematics. The area of a rectangle is given by the product of its length and width, and the perimeter is the sum of the lengths of all sides.
Given that the area of the farm is 750 m² and the total fencing used is 110 m, you can formulate 2 equations. If we let the width be w, and the length be l, we have:
We can solve these equations to find the values of w and l. From that, we'll get the dimensions of the rectangular farm.
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