Is three forths bigger than four fifths

Answers

Answer 1

Answer: no, 4/5 is bigger than 3/4 because when you find the common denominator between the two 4/5 becomes 16/20 while 3/4 becomes 15/20.

wish it helps

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Compare new france and the 13 colonies in the terms of population, government and economy

Answers

Answer:

5 or

Step-by-step explanation:

Five times a number is 40. What is the number?
equation:

n =

Answers

5n = 40
n = 8 (Divide everything by five)

If you need further help just ask.

Rachna has nickels, dimes, and quarters in her piggy bank. She has $4.65 altogether. She has three more quarters than dimes and twice as many nickels as quarters. How many quarters does Rachna have? a.8
b.11
c.22
d.41

Answers

the value of the coin times the number of coins equals the total value
so
0.05n + 0.10d + 0.25q = 4.65

the we are given that there are "three more quarters than dimes"
this translates to
q = d + 3
or
d = q - 3

then we are also given that there are "twice as many nickels as quarters"
this translates to
n = 2q

we plug d = q - 3 and n=2q
into the first equation and solve for q
0.05(2q) + 0.10(q-3) + 0.25q = 4.65

we distribute/multiply
0.10q + 0.10q - 0.30 + 0.25q = 4.65

then add like terms
0.45q - 0.30 = 4.65

then add 0.30 to both sides
0.45q = 4.95

then divide both sides by 0.45
and we get
q = 4.95/0.45 = 11

therefore there are 11 quarters

Which of the following expressions would give the number of ways to choose a group of 7 from a group of 15?

Answers

The formula is ¹⁵C₇. Then the number of ways to choose a group of 7 from a group of 15 will be 6435.

What are permutation and combination?

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

Then the number of ways to choose a group of 7 from a group of 15 will be given by the combination formula.

Then we have

Number of ways = ¹⁵C₇

Number of ways = 6435

More about the permutation and the combination link is given below.

brainly.com/question/11732255

#SPJ2

You didn't supply any expressions, but it'd be one of these (assuming it's unique combinations, rather than the duplicate permitting permutations):
(15!)/(7!(15-7)!)
or
(15!)/(7!8!)
or
(15•14•13•12•11•10•9)/(7!)
or
(15•14•13•12•11•10•9)/(7•6•5•4•3•2)
or
32432400/5040
or
6435

depending on what it has as possible answers.

Divide z by 11. Then, add 8.