Lisa is cooking muffins.The recipe calls for 7 cups of sugar. She has already put in 2 cups. Hpw many more cups does she need to put in?

Answers

Answer 1

Answer: Well, if she already put in 2, and she needs seven, then all you need to do is subtract. So, 7-2 equals: 5
She needs 5 more cups of sugar.

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The area of the base of a rectangular juice box is 4.5 square inches. If the volume of the box is 18 cubic inches, how tall is the box? Is the answer 4 right or wrong.

Answers

Volume=base area*height
18=4.5*x
x=18/4.5 = 4 :your answer is correct.

Please work out 6-3x-2--10

Answers

SO
   6-3X-2 -(- 10 ) WE HAVE TO COMBINE LIKE TERMS
   6-3X-2 +10
   6-3X +8
   6+8-3X
   14+(-3X )
   14-3X

- ( - 10 ) = + 10 ;
- 2 + 10 = + 8 ;
6 + 8 = 14 ;
Finally, 14 - 3X ;

Write the product using exponents: 1/3 • 1/3 • 1/3

Using exponents, the product is ______ .

Answers

\frac{1}{3} ^{3} = 1/3 • 1/3 • 1/3

jamal finished 5/6 of his homework. Margaret finished 3/4 of her homework, and Steve finished 10/12 of his homework. Which two students finished the same amount of homework?

Answers

Answer:

Jamal and Steve

Step-by-step explanation:

we have that

Jamal finished $(5)/(6)$ of his homework

Margaret finished $(3)/(4)$ of his homework

Steve finished $(10)/(12)$ of his homework

Simplify Steve's homework ------> $(10)/(12)$

Divide by $2$ both numerator and denominator

$(10)/(12)=((10/2))/((12/2))=(5)/(6)$

therefore

Steve's homework=Jamal's homework

Suppose two 1-6 number cubes are rolled. find the probability of each outcome. P(1 or 5)

Answers

Answer:

The probability of each outcome rolling two numbered cubes is 1/36 or 2.8% (Rounding to the next tenth)

Step-by-step explanation:

Probability of each outcome with one cube = Number of favorable events for each outcome/Total number of possible events

Replacing with the real values, we have:

Probability of each outcome with one cube = 1/6

Probability of each outcome with two cubes = 1/6 * 1/6 = 1/36

The probability of each outcome rolling two numbered cubes is 1/36 or 2.8% (Rounding to the next tenth)

Three sides of a regular polygon with 8 sides are chosen at random. Find the probability that, when these sides are extended, they form a triangle containing the polygon.

Answers

$|\Omega|={8\choose 3}=(8!)/(3!5!)=(6\cdot7\cdot8)/(6)=7\cdot8=56$

There are two possibilities of choosing three sides of the polygon, so when they are extended, they form a triangle containing the polygon (pictures in the attachment). Multiplying it by the number of sides, gives us 16 possibilities in total.

$|A|=16\n\nP(A)=(|A|)/(|\Omega|)\nP(A)=(16)/(56)=(2)/(7)$

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In the parallelogram, angle QRP = 32 and angle PRS = 84. find angle PQR.